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mariarad [96]
3 years ago
11

Which statement correctly describes momentum? It is a scalar quantity because it involves magnitude only. It is a scalar quantit

y because it involves magnitude and direction. It is a vector quantity because it involves magnitude and direction. It is a vector quantity because it involves magnitude only.
Physics
1 answer:
Llana [10]3 years ago
4 0
<span>It is a vector quantity because it involves magnitude and direction.</span>
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What type of image can be larger or smaller than the object?
Stolb23 [73]
It’s D. An enlargement (hope this helps!)
4 0
3 years ago
A professor drives off with his car (mass 870 kg), but forgot to take his coffee mug (mass 0.47 kg) off the roof. The coefficien
SSSSS [86.1K]

Answer:6.86 m/s^2

Explanation:

Given

mas of car=870 kg

coffee mug mass=0.47 kg

coefficient of static friction between mug and roof \mu _s= 0.7

Coefficient of kinetic Friction \mu _k=0.5

maximum car acceleration is \mu \times g

here coefficient of static friction comes in to action because mug is placed over car . If mug is moving relative to car then \mu _k is come into effect

a_{max}=0.7\times 9.8=6.86 m/s^2

8 0
3 years ago
In a science museum, a 140 kg brass pendulum bob swings at the end of a 16.8 m -long wire.
Mice21 [21]

The period of the pendulum is 8.2 s

Explanation:

The period of a simple pendulum is given by the equation:

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration of gravity

T is the period

We notice that the period of a pendulum does not depend at all on its mass, but only on its length.

For the pendulum in this problem, we have

L = 16.8 m

and

g=9.8 m/s^2 (acceleration of gravity)

Therefore the period of this pendulum is

T=2\pi \sqrt{\frac{16.8}{9.8}}=8.2 s

#LearnWithBrainly

3 0
3 years ago
Why do some scientists think that Irr II galaxies have irregular, distorted shapes?
laila [671]
They believe the distortions happened when two galaxies collided.

Hope This Helps :)
3 0
3 years ago
Consider steady-state conditions for one-dimensional conduction in a plane wall having a thermal conductivity k = 50 W/m · K and
tatuchka [14]

Answer:

solution:

dT/dx =T2-T1/L

&

q_x = -k*(dT/dx)

<u>Case (1)  </u>

dT/dx= (-20-50)/0.35==> -280 K/m

 q_x  =-50*(-280)*10^3==>14 kW

Case (2)

dT/dx= (-10+30)/0.35==> 80 K/m

 q_x  =-50*(80)*10^3==>-4 kW

Case (2)

dT/dx= (-10+30)/0.35==> 80 K/m

 q_x  =-50*(80)*10^3==>-4 kW

Case (3)

q_x  =-50*(160)*10^3==>-8 kW

T2=T1+dT/dx*L=70+160*0.25==> 110° C

Case (4)

q_x  =-50*(-80)*10^3==>4 kW

T1=T2-dT/dx*L=40+80*0.25==> 60° C

Case (5)

q_x  =-50*(200)*10^3==>-10 kW

T1=T2-dT/dx*L=30-200*0.25==> -20° C

note:

all graph are attached

6 0
3 years ago
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