A large male cougar living in the Cascade Mountains kills a deer or elk every 9 to 12 days, eating up to 20 pounds at a time and burying the rest for later.Except for females with young, cougars are lone hunters that wander between places frequented by their prey, covering as much as 15 miles in a single night.Cougars rely on short bursts of speed to ambush their prey. A cougar may stalk an animal for an hour or more
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The answer is B because solids have a definite shape and volume
Answer:
Power = 13.5744 kilowatts
Explanation:
Power is the rate at which work is done. ... Great power means a large amount of work or energy developed in a short time. For example, when a powerful car accelerates rapidly, it does a large amount of work and consumes a large amount of fuel in a short time.
Formula for power = work/time
= IVT/T
= IV
Where I is the current
And V is the voltage
The voltage V supply = 168 v
The current A supply = 80.8 A
Power = 80.8*168
Power = 13574.4 watts
Power = 13.5744 kilowatts
Answer:
The the linear speed (in m/s) of a point on the rim of this wheel at an instant=0.418 m/s
Explanation:
We are given that
Angular acceleration, ![\alpha=3.3 rad/s^2](https://tex.z-dn.net/?f=%5Calpha%3D3.3%20rad%2Fs%5E2)
Diameter of the wheel, d=21 cm
Radius of wheel,
cm
Radius of wheel, ![r=\frac{21\times 10^{-2}}{2} m](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B21%5Ctimes%2010%5E%7B-2%7D%7D%7B2%7D%20m)
1m=100 cm
Magnitude of total linear acceleration, a=![1.7 m/s^2](https://tex.z-dn.net/?f=1.7%20m%2Fs%5E2)
We have to find the linear speed of a at an instant when that point has a total linear acceleration with a magnitude of 1.7 m/s2.
Tangential acceleration,![a_t=\alpha r](https://tex.z-dn.net/?f=a_t%3D%5Calpha%20r)
![a_t=3.3\times \frac{21\times 10^{-2}}{2}](https://tex.z-dn.net/?f=a_t%3D3.3%5Ctimes%20%5Cfrac%7B21%5Ctimes%2010%5E%7B-2%7D%7D%7B2%7D)
![a_t=34.65\times 10^{-2}m/s^2](https://tex.z-dn.net/?f=a_t%3D34.65%5Ctimes%2010%5E%7B-2%7Dm%2Fs%5E2)
Radial acceleration,![a_r=\frac{v^2}{r}](https://tex.z-dn.net/?f=a_r%3D%5Cfrac%7Bv%5E2%7D%7Br%7D)
We know that
![a=\sqrt{a^2_t+a^2_r}](https://tex.z-dn.net/?f=a%3D%5Csqrt%7Ba%5E2_t%2Ba%5E2_r%7D)
Using the formula
![1.7=\sqrt{(34.65\times 10^{-2})^2+(\frac{v^2}{r})^2}](https://tex.z-dn.net/?f=1.7%3D%5Csqrt%7B%2834.65%5Ctimes%2010%5E%7B-2%7D%29%5E2%2B%28%5Cfrac%7Bv%5E2%7D%7Br%7D%29%5E2%7D)
Squaring on both sides
we get
![2.89=1200.6225\times 10^{-4}+\frac{v^4}{r^2}](https://tex.z-dn.net/?f=2.89%3D1200.6225%5Ctimes%2010%5E%7B-4%7D%2B%5Cfrac%7Bv%5E4%7D%7Br%5E2%7D)
![\frac{v^4}{r^2}=2.89-1200.6225\times 10^{-4}](https://tex.z-dn.net/?f=%5Cfrac%7Bv%5E4%7D%7Br%5E2%7D%3D2.89-1200.6225%5Ctimes%2010%5E%7B-4%7D)
![v^4=r^2\times 2.7699](https://tex.z-dn.net/?f=v%5E4%3Dr%5E2%5Ctimes%202.7699)
![v^4=(10.5\times 10^{-2})^2\times 2.7699](https://tex.z-dn.net/?f=v%5E4%3D%2810.5%5Ctimes%2010%5E%7B-2%7D%29%5E2%5Ctimes%202.7699)
![v=((10.5\times 10^{-2})^2\times 2.7699)^{\frac{1}{4}}](https://tex.z-dn.net/?f=v%3D%28%2810.5%5Ctimes%2010%5E%7B-2%7D%29%5E2%5Ctimes%202.7699%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D)
![v=0.418 m/s](https://tex.z-dn.net/?f=v%3D0.418%20m%2Fs)
Hence, the the linear speed (in m/s) of a point on the rim of this wheel at an instant=0.418 m/s
C. 2000 calories.
Explanation/calculation:
Specific heat capacity = calories / mass * (final temperature - initial temperature)
1 = calories / 100 * (60 - 40)
1 = calories / 100 * 20
1 * (100 * 20) = calories
1 * 2000 = calories
2000 = calories