Describe how valence electrons from these elements behave when forming metallic bonds:

1 answer:

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Well depending on the elements, valence electrons that don’t have a complete outer shell are attracted to others to either steal or give away a valence electrons to have a complete shell, or they’ll share and form bonds...but the missing valence electrons depends on the elements

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1C. You just have made unstable atoms.How can you make them stable?

Leokris [45]

Answer:

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Explanation:

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2 years ago

For the reaction 2NH3(g)↽−−⇀3H2(g)+N2(g) 2 NH 3 ( g ) ↽ − − ⇀ 3 H 2 ( g ) + N 2 ( g ) the equilibrium concentrations were found

forsale [732]

Answer:

0.324

Explanation:

The following data were obtained from the question:

Concentration of NH3, [NH3] = 0.25 M

Concentration of H2, [H2] = 0.3 M

Concentration of N2, [N2] = 0.75 M

Equilibrium constant (Kc) =.?

The balanced equation for the reaction is given below:

2NH3 <==> 3H2 + N2

The equilibrium constant, Kc for a given reaction is the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient. Thus, the equilibrium constant for the above reaction can be obtained as illustrated below:

Kc = [H2]³ [N2] / [NH3]²

Concentration of NH3, [NH3] = 0.25 M

Concentration of H2, [H2] = 0.3 M

Concentration of N2, [N2] = 0.75 M

Equilibrium constant (Kc) =.?

Kc = [H2]³ [N2] / [NH3]²

Kc = [0.3]³ × [0.75] / [0.25]²

Kc = (0.027 × 0.75) / 0.0625

Kc = 0.02025 / 0.0625

Kc = 0.324

Therefore, the equilibrium constant for the reaction is 0.324

4 0