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liubo4ka [24]
3 years ago
6

What type of spectrum is produced when electromagnetic radiation is emitted or absorbed as electrons change energy levels in an

atom?
Chemistry
2 answers:
Setler79 [48]3 years ago
8 0
Then as the electrons in the atoms fall back down, they emit electromagnetic radiation (light). The amount of light emitted at different wavelengths, called the emission spectrum, is shown for a discharge tube filled with hydrogen gas in Figure 12.6 below.
ArbitrLikvidat [17]3 years ago
6 0

Answer:

this is the answer hope it is correct by the way hi

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What is a temperature scale used by scienctist?
laila [671]
To measure the kinetic engery  from the inside and outside of something to be able to tell how hot or coll something is.. without touching it also
3 0
3 years ago
Find the kinetic energy of a boy of mass 6.5kg running at a velocity of 6.0m/s​
ololo11 [35]

Explanation:

Given,

M=6.5kg,velocity(v)=6m/s

K.E=1/2mv^2

=1/2×6.5×6^2

=1/2×6.5×36

=18×6.5

=117 J

3 0
3 years ago
Suppose that 2.14 grams of H2SO4 is mixed with enough water to make 225 mL of solution. Determine the Molarity (M) of the soluti
Alik [6]

Answer:

0.0970 M

Explanation:

Remember this equation:

mol/M x V

Convert it so that you can get M.

M=mol/V

Convert the 2.14 grams of H2SO4 into mols

=0.0218

Convert mL to L

225/1000

=0.225

Plug it in.

0.0218/0.225

=0.0970 M

6 0
3 years ago
Select the correct hybridization for the central atom based on the electron geometry cocl2 (carbon is the central atom).
Rainbow [258]
In this compound (Phosgene) the central atom (carbon is Sp² Hybridized).

Sp, Sp² and Sp³ can be calculated very simply by doing three steps, 

Step 1:
           Assume triple bond and double bond as one bond and assign s or p to it. In this example carbon double bond oxygen is considered once and let suppose it is s. Now we are having our s.

Step 2:
          Count lone pair of electron, each lone pair counts for s and p. In this case there is no lone pair of electron on carbon, so not included.

Step 3:
          Count single bonds for s and p. As we have already assigned s to the double bond, now one p for one single bond, and other p for the other single bond.

Result:
          So, we counted 1 s for double bond, 1 p for one single and other p for second single bond. As a whole we got,

                                                       Sp²

Practice:
You can practice for hybridization of Oxygen in this molecule. Oxygen has 2 lone pair of electrons. (Hint: Sp² Hybridization)
7 0
3 years ago
Hydrogen chloride gas and oxygen gas react to form water and chlorine gas. A reaction mixture initially contains 53.2 g of hydro
Sergio [31]

<u>Answer:</u> The mass of the excess reactant (oxygen gas) is 3.136 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For HCl:</u>

Given mass of HCl = 53.2 g

Molar mass of HCl = 36.5 g/mol

Putting values in equation 1, we get:

\text{Moles of HCl}=\frac{53.2g}{36.5g/mol}=1.46mol

  • <u>For oxygen gas:</u>

Given mass of oxygen gas = 26.5 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen gas}=\frac{26.5g}{32g/mol}=0.828mol

The chemical equation for the reaction of HCl and oxygen gas follows:

2HCl+O_2\rightarrow H_2O+Cl_2

By Stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of oxygen gas

So, 1.46 moles of HCl will react with = \frac{1}{2}\times 1.46=0.73mol of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, HCl is considered as a limiting reagent because it limits the formation of product.

Excess moles of oxygen gas = (0.828 - 0.73) = 0.098 moles

Now, calculating the mass of oxygen gas from equation 1, we get:

Molar mass of oxygen gas = 32 g/mol

Excess moles of oxygen gas = 0.098 moles

Putting values in equation 1, we get:

0.098mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.098mol\times 32g/mol)=3.136g

Hence, the mass of the excess reactant (oxygen gas) is 3.136 grams

4 0
3 years ago
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