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Yuri [45]
3 years ago
7

How much co2 is realsed by burning trash

Chemistry
1 answer:
V125BC [204]3 years ago
3 0
A lot ...................
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When solid ammonium chloride dissociates at a certain temperature in a 0.500 dm3 container, ammonia and hydrogen chloride are fo
SIZIF [17.4K]
1) Reaction

<span>NH4Cl(s) ---> NH3(g) + HCl(g)


2) equilibrium equation, Kc


Kc = [NH3] * [HCl]


3) Table of equilibrium formation



step               concentrations
                       </span>
<span>                            NH4Cl(s)                     NH3(g)             HCl(g)


start                      1.000 mole                     0                    0


react                        - x


produce                                                       +x                  + x
                         ------------------                ----------              -----------

end                         1 - x                             +x                    +x
            

1 - x = 0.3 => x = 1 - 0.3 = 0.7


[NH3] = [HCl] = 0.7/0.5 liter = 1.4                (I used 0.500 dm^3 = 0.5 liter)


4) Equilibrium equation:


Kc = [NH3] [HCl] = (1.4)^2  = 1.96


Which is the number that you were looking for.


Answer: Kc = 1.96
</span>
8 0
3 years ago
Which is the BEST evidence that a chemical change has occurred?
MaRussiya [10]

d///////////////////////////////

3 0
3 years ago
Select all that are True.
givi [52]
Answers a
Explanation
Because it removes all the energy in the form of heat
4 0
2 years ago
As you travel from a solid to a gas, energy is being absorbed or given off?
Wittaler [7]
Sublimation is solid to a gas, during the process of sublimation energy is absorbed.
5 0
3 years ago
How many moles of O2 are needed to burn 2.56 moles of CH3OH?
lukranit [14]

Answer:

n_{O_2}=3.84molO_2

Explanation:

Hello!

In this case, since the combustion reaction of methanol is:

CH_3OH+\frac{3}{2} O_2\rightarrow CO_2+2H_2O

In such a way, since there is 1:3/2 mole ratio between methanol and oxygen, we can compute the moles of oxygen that are needed to burn 2.56 moles of methanol as shown below:

n_{O_2}=2.56molCH_3OH*\frac{\frac{3}{2}molO_2}{1molCH_3OH} \\\\n_{O_2}=3.84molO_2

Best regards!

6 0
2 years ago
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