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3 years ago

Which term describes this reaction?

Chemistry

1 answer:

yuradex [85]3 years ago

7 0

Answer:

addition

Explanation:

I really don't know why

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which number should be placed before F2 on the reactants side equation to make equation balanced? Xe + ___F2 > XeF4

Ivahew [28]

There are four F atoms on the products side.

Since two more F atoms are required on the reactant side, you multiply the number of F2 molecules by two.

So 2 should be placed in front of F2

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3 years ago

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(PLZ HELP ME ON THIS!!!) Which of the following will change if you apply unbalanced forces to an object?

S_A_V [24]

D) Its position changes because the unbalanced forces move the object.

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4 years ago

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How does the size of ions affect the conductivity of a solution?

mrs_skeptik [129]

Small ions have small areas. There is less resistance as they move through the solution.

For example, in molten salts, the conductivity of Li+ is greater than that of Cs+.

Small ions have high charge density.

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3 years ago

An ion always has a ________ or ________ charge. While a covalent bond always has no _________, meaning it is __________.

almond37 [142]

An ion has a positive or negative charge. While a covalent bond always has no charge, meaning it is neutral.

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4 years ago

If 27.3% of a sample of silver-112 decays in 1.52 hours, what is the half-life (in hours to 3 decimal places)?

ICE Princess25 [194]

Answer: The half life of the sample of silver-112 is 3.303 hours.

Explanation:

All radioactive decay processes undergoes first order reaction.

To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:

$k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}$

where,

k = rate constant = ?

t = time taken = 1.52 hrs

$[A_o]$ = Initial concentration of reactant = 100 g

[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g

Putting values in above equation, we get:

$k=\frac{2.303}{1.52hrs}\log \frac{100}{72.7}\\\\k= 0.2098hr^{-1}$

To calculate the half life period of first order reaction, we use the equation:

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life period of first order reaction = ?

k = rate constant = $0.2098hr^{-1}$

Putting values in above equation, we get:

$t_{1/2}=\frac{0.693}{0.2098hr^{-1}}\\\\t_{1/2}=3.303hrs$

Hence, the half life of the sample of silver-112 is 3.303 hours.

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3 years ago