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asambeis [7]
4 years ago
12

The union of two events A and B is the event that: a) The intersection of A and B does not occur. b) Both A and B occur. c) Eith

er A or B or both occur. d) Either A or B, but not both occur. e) A and B occur at the same time. f) None of the above
Mathematics
1 answer:
Wewaii [24]4 years ago
6 0

Answer:

c) Either A or B or both occur.

Step-by-step explanation:

Suppose that we have two events

Event A

Event B

We have that:

A = a + (A \cap B)

In which a a happens and b does not and A \cap B is the probability that aboth events happen

By the same logic, we have that:

B = b + (A \cap B)

The union of events A and B is:

(A \cup B) = a + b + (A \cap B)

Which includes either one of them or both.

So the correct answer is:

c) Either A or B or both occur.

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A comedy show sells lower level tickets for $77 and upper level tickets for $99. On the opening night 2615 tickets were sold for
babunello [35]

Let x represent lower level tickets that cost $77

Let y represent upper level tickets that cost $99

Cost equation: 77x + 99y = 247,071

Tickets equation: x + y = 2615

Using the elimination method, multiply the second equation by -77:

77x + 99y = 247,071

-77x - 77y = -201,355

--> 22y = 45,716

--> y = 2,078

Now plug "y" into either equation and solve for "x". I chose the Tickets equation. x + y = 2615 → x = 2615 - y → x = 2615 - 2078 → x = 537

Answer: lower level = 537 tickets, upper level = 2078 tickets.


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3 years ago
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2 years ago
The number of bagels sold daily for two bakeries is shown in the table:
ivann1987 [24]

Going by the data given, the best center of distribution to use in terms of mean and median is D) Mean for Bakery A because the data is symmetric; median for Bakery B because the data is not symmetric.

<h3>What centers of distribution should be used?</h3>

The mean should be used for data sets that are symmetric while the median should be used for data that is not symmetric.

The data is said to be symmetric when the mean and median are equal or very close.

Bakery A mean:

= (45 + 52 + 51  48 + 61 + 34 + 55  46) / 8

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Bakery A median is 49.5

Bakery B mean:

= (48  42 + 25  45 + 57 + 10 + 43 + 46 ) / 8

= 39.5

Bakery B median is 44.

This shows that Bakery A data is symmetric so the best center of distribution to use is mean.

Bakery B is not symmetric so the center of distribution to use is median.

Find out more on symmetric data at brainly.com/question/7130507

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2 years ago
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Answer:

a

Step-by-step explanation:

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C would be correct
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