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cluponka [151]
3 years ago
11

MUSIC

Physics
2 answers:
liberstina [14]3 years ago
8 0

Answer:

true

Explanation:

Dmitrij [34]3 years ago
7 0

Answer:

false

Explanation:

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What happens when a sound wave passes from water into air?
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4 years ago
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how many bits are required to sample an incoming signal 4000 times per second using 64 different amplitude level
Gelneren [198K]

Answer:

6 bits

Explanation:

The quality of digitized signal can be improved by reducing quantizing error. This is done by increasing the number of amplitude levels, thereby minimizing the difference between the levels and hence producing a smoother signal.

Also, Sampling frequently (also known as oversampling) can help in improving signal quality.

To get the number of bits, we use:

2ⁿ = amplitude level

where n is the number of bits.

Given an amplitude level of 64, hence:

2ⁿ = 64

2ⁿ = 2⁶

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3 years ago
Is this a scientific model? Use complete sentences to explain why or why not.
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If you are swimming upstream (i.e., against the current), at what speed does your friend on the shore see you moving?
Alex777 [14]
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7 0
4 years ago
A weather balloon is designed to expand to a maximum radius of 24 m at its working altitude, where the air pressure is 0.030 atm
nlexa [21]

Answer:

<em>Radius at liftoff 8.98 m</em>

Explanation:

At the working altitude;

maximum radius = 24 m

air pressure = 0.030 atm

air temperature = 200 K

At liftoff;

temperature = 349 K

pressure = 1 atm

radius = ?

<em>First, we assume balloon is spherical in nature,</em>

<em>and that the working gas obeys the gas laws.</em>

from the radius, we can find the volume of the balloon at working atmosphere.

Volume of a sphere = \frac{4}{3} \pi r^{3}

volume of balloon = \frac{4}{3} x 3.142 x 24^{3} = 57913.34 m^3

using the gas equation,

\frac{P1V1}{T1} = \frac{P2V2}{T2}

<em>The subscript 1 indicates the properties of the gas at working altitude, and the subscript 2 indicates properties of the gas at liftoff.</em>

imputing values, we have

\frac{0.03*57913.34}{200} = \frac{1*V2}{349}

0.03 x 57913.34 x 349 = 200V2

V2 = 606352.67/200 = <em>3031.76 m^3  this is the volume occupied by the gas in the balloon at liftoff.</em>

from the formula volume of a sphere,

V =  \frac{4}{3} \pi r^{3} =  \frac{4}{3} x 3.142 x r^{3} = 3031.76

4.19r^{3}  = 3031.76

r^{3} = 3031.76/4.19  

radius r of the balloon on liftoff = \sqrt[3]{723.57} = <em>8.98 m</em>

4 0
3 years ago
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