The resultant acceleration of the box is 0.055 m/s² in the direction of the greater force.
The given parameters:
- Mass of the box, m = 31 kg
- Two applied forces, = 8.3 N and 6.6 N
<h3>Resultant force on the box</h3>
The resultant force on the box is calculated as follows;
<h3>Resultant acceleration of the box</h3>
The resultant acceleration of the box is calculated as follows;
Thus, the resultant acceleration of the box is 0.055 m/s² in the direction of the greater force.
Learn more about resultant acceleration here: brainly.com/question/26216029
In a particle accelerator a positron (C= +1.6 x 10-19) travels through a perpendicular magnet field with a magnitude
of 3.1 x 10-2 T. At what speed must the positron travel in order for it to experience a force of 4.75 x 10-14 N?
28. An alpha particle (2 protons and 2 neutrons) experiences a downward force of 2.9 x 10-14 N while traveling in a
magnetic field with a strength of 5.1 x 10-19 T pointing to the north. Find the speed of the particle and the direction
it must be traveling in.
29. Find the length of a wire if it experiences a .63N force when it travels through a magnetic field with a strength of
0.85T whilst carrying 5.0 amps of current.
30. A coil with 462 turns of wire, a total resistance of 36Ω , and a cross-sectional area of 0.25 m2
is positioned with its
plane perpendicular to the field of a powerful electromagnet. What average current is induced in the coil during the 0.37s
that the magnetic field drops from 3.1 T to 0.0 T?
31. A step-up transformer has a potential difference across the primary of 28 V and a potential difference across the
secondary of 3.0 × 104
V. There are 28 turns in the primary coil. How many turns are in the secondary?
32. A step-up transformer is used to create a potential difference of 1.6872 × 105
V across the secondary. The potentia
We can solve the problem by using Ohm's law, which states that an Ohmic conductor the following relationship holds:
where
is the potential difference applied to the resistor
I is the current flowing through it
R is the resistance
In our problem, I=4.00 A and
, so the potential difference is
12m S=0m E, -12m N
15m 55d E of N = 15 sin 55, 15 cos 55 N
Sum= (15sin55)m E, (-12 + 15 cos 55)m N
Because it demonstrates the relationship between a body and the forces acting upon it, and its motion in response to those forces. [Hope that helps]
