The atom in the diagram has neutral charge. How many protons does it have

The yellow balls represent neutrons and have a neutral charge. <br><br><br> true<br> false

Paul [167]

Yes the answer is true

7 0

4 years ago

Jack and Jill are maneuvering a 3300 kg boat near a dock. Initially the boat's position is < 2, 0, 3 > m and its speed is

Paraphin [41]

Answer:

The workdone by Jack is $W_{jack} = -1050J$

The workdone by Jill is $W_{Jill} = 0J$

The final velocity is $v = 1.36 m/s$

Explanation:

From the question we are given that

The mass of the boat is $m_b = 3300kg$

The initial position of the boat is $P_i = (2 \r i + 0 \r j + 3\r k)m$

The Final position of the boat is $P_f = (4\r i + 0 \r j + 2\r k )\ m$

The Force exerted by Jack $\r F = (-420\r i + 0 \r j + 210\r k) \ N$

The Force exerted by Jill $\r F_{Jill} =(180 \r i + 0\r j + 360\r k)$

Now to obtain the displacement made we are to subtract the final position from the initial position

$\r P = P_f - P_i$

$= (4\r i + 0\r j + 2 \r k) - (2\r i + 0\r j + 3\r k )$

$= (2\r i + 0\r j -\r k )m$

Now that we have obtained the displacement we can obtain the Workdone

which is mathematically represented as

$W =\r F * \r P$

The amount of workdone by jack would be

$W_{jack} =\r F * \r P$

$= [(-420\r i +0\r j +210\r k)(2\r i + 0\r j - \r k)]$

$= (-420) (2) + (210)(-1)$

$= -840 - 210$

$=-1050J$

The amount of workdone by Jill would be

$W_{Jill} =\r F * \r P$

$= [(180 \r i + 0\r j + 360\r k)(2\r i +0\r j -\r k)]$

$= (180 )(2) +(360)(-1)$

$=0J$

According to work energy theorem the Workdone is equal to the kinetic energy of the boat

$W = K.E = \frac{1}{2} m *[v^2 - (1.1)^2]$

$-1050 = 0.5*3300 [*v^2- (1.1)^2]$

$-1050 = 1650 [v^2 -1.21]$

$0.6363 = v^2 -1.21$

$v^2 = 0.6363+1.21$

$v^2 =1.846$

$v = 1.36\ m/s$

6 0

4 years ago

You drive a car 660 m to the east, then 400 m to the north. What is the magnitude of your displacement? Using a sketch, estimate

ANEK [815]

Explanation:

You walk 53m to the north, then you turn 60° to your right and walk another 45m. Determine the direction of your displacement vector. Express your answer as an angle relative to east.

8 0

3 years ago

Two cars are moving. The first car has twice the mass of the second car but only half as much kinetic energy. When both cars inc

Zanzabum

Answer:

20 mi

Exp3tanation:

I did the same question in a quizz

8 0

3 years ago

IF EARTH HAD NO ATMOSPHERE, WOULD A FALLING OBJECT EVER REACH TERMIONAL VELOCITY?

EleoNora [17]

No. What most people call 'terminal velocity' is the speed of the falling
object when the downward force of gravity is equal to the upward force
of air resistance. At that speed, the vertical forces on the object are
balanced, so it stops accelerating, and falls at a constant speed.

If there were no atmosphere, there would be no upward force due to
air resistance. The falling object would continue to accelerate all the
way down until it went 'splat'.

This is exactly the situation for meteoroids or asteroids falling onto the Moon.

3 0

4 years ago