Question

Using the elimination method how do I find x and y for the following problem:

Answer 1

Answer: x= -2 and y= -3.

Step-by-step explanation:

The given system of equations :

4x-7y=13    ...(i)

4x + 7y = -29​     ....(ii)

By Elimination method, Eliminating (ii) from (i) , we get

$-7y-7y=13-(-29)\\\\\Rightarrow\ -14y=13+29\\\\\Rightarrow\ -14y=42\\\\\Rightarrow\ y=\dfrac{42}{-14}\\\\\Rightarrow\ y=-3$

Now, Adding (i) and (ii), we get

$8x=-16\\\\\Rightarrow\ x=\dfrac{-16}{8}\\\\\Rightarrow\ x=-2$

Hence, the solution is : x= -2 and y= -3.