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bearhunter [10]
4 years ago
7

Erica walked down a trail into a valley. V(d) models Erica's vertical distance from the top of the valley (in kilometers) after

walking d kilometers along the trail. What does the statement V(2)= T mean?
A= Erica's vertical distance from the top of the valley was the same after she had walked 2 km  and after she had walked T kilometers.
B= After she had walked 2 km along the trail, Erica's vertical distance from the top of the valley was equal to T kilometers.
C= After she had walked T kilometers along the trail, Erica's vertical distance from the top of the valley was equal to 2 km
Mathematics
2 answers:
zhenek [66]4 years ago
6 0

Answer:

<u>THE ANSWER IS B.</u>

Step-by-step explanation:

After she had walked 2K along the trail, Erica's vertical distance from the top of the valley was equal to T kilometers.

I just checked it and this was the right answer.

nikitadnepr [17]4 years ago
4 0

Answer:

for all the khan academy  ppl

its B

After She walked 2km

Step-by-step explanation:

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a company that manufactures bicycles has a fixed cost of $80,000. it costs $100 to produce each bicycle. the total cost for the
frez [133]

C(x) = 80000 + 100x is the total cost as function of number of cycles produced

C(90) = 89000 and it costs $ 89000 to produce 90 bicycles

<em><u>Solution:</u></em>

Given that, company that manufactures bicycles has a fixed cost of $80,000

Fixed cost = $ 80,000

Let x be the number of cycles produced

Let C(x) be the total cost as function of number of cycles produced

It costs $100 to produce each bicycle

Variable cost = 100 x number of cycles produced

variable cost = 100x

The total cost for the company is the sum of its fixed cost and variable costs

total cost = fixed cost + variable cost

C(x) = 80000 + 100x

Thus total cost as function of "x" is found

<em><u>Find and interpret C(90)</u></em>

Substitute x = 90 in C(x)

C(90) = 80000 + 100(90)

C(90) = 80000 + 9000

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3 0
3 years ago
In the past, the average age of employees of a large corporation has been 40 years. Recently, the company has been hiring older
Viktor [21]

Answer:

p_v =P(t_{(63)}>2.5)=0.0075  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=45 represent the mean height for the sample  

s=16 represent the sample standard deviation for the sample  

n=64 sample size  

\mu_o =40 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean age is higher than 40 years, the system of hypothesis would be:  

Null hypothesis:\mu \leq 40  

Alternative hypothesis:\mu > 40  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{45-40}{\frac{16}{\sqrt{64}}}=2.5    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=64-1=63  

Since is a one right tailed test the p value would be:  

p_v =P(t_{(63)}>2.5)=0.0075  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.  

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