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3 years ago

A gas was at STP. If the pressure increased to 3.5 atm, what would the new temperature be?

Chemistry

1 answer:

disa [49]3 years ago

3 0

Answer:

T₂ = 956.0 K

Explanation:

Given data:

Initial temperature = 273.15 K

Initial pressure = 1 atm

Final pressure = 3.5 atm

Final temperature = ?

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

1 atm / 273.15 K = 3.5 atm / T₂

T₂ = 3.5 atm ×273.15 K / 1 atm

T₂ = 956.0 atm. K / 1 atm

T₂ = 956.0 K

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Baking soda NaHCO3, is made from soda ash, a common name for sodium carbonate. The soda ash is obtained in two ways. It can be m

Vaselesa [24]

Answer:

Explanation:

From the given information:

mass of silver chloride AgCl = 11.89 g

molar mass of AgCl = 143.37 g/mol

We know that:

number of moles = mass/molar mass

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number of moles of AgCl = 11.89 g/ 143.37 g/mol

number of moles of AgCl = 0.0829 mol

The chemical equation for the mineral called trona is:

$\mathsf{Na_2CO_3.NaHCO_3.2H_2O}$

when being reacted with hydrochloric acid, we have:

$\mathsf{Na_2CO_3.NaHCO_3.2H_2O + 3HCl \to 3NaCl + 2CO_2 +4H_2O}$

One mole of NaCl formed from one mole of trona sample = 0.0829 moles of AgCl

i.e. 0.0829 moles of NaCl can be formed from AgCl

mass of trona sample = number of moles × molar mass

mass of trona sample = 0.0829 × 226

mass of trona sample = 18.735 g

The mass in the percentage of NaHCO₃ = mass of NaHCO₃/ mass of trona

The mass in the percentage of NaHCO₃ = 6.93/18.735

The mass in the percentage of NaHCO₃ = 0.36989

The mass in the percentage of NaHCO₃ = 36.99%

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6.78 g sample manufactured from Na₂CO₃ is purer.

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