Answer:
1.64 moles O₂
Explanation:
Part A:
Remember 1 mole of particles = 6.02 x 10²³ particles
So, the question becomes, how many '6.02 x 10²³'s are there in 9.88 x 10²³ molecules of O₂?
This implies a division of given number of particles by 6.02 x 10²³ particles/mole.
∴moles O₂ = 9.88 x 10²³ molecules O₂ / 6.02 x 10²³ molecules O₂ · mole⁻¹ = 1.64 mole O₂
_______________
Part B needs an equation (usually a combustion of a hydrocarbon).
Answer:
119.85 grams Br or 120. grams Br (sig figs)
Explanation:
1.50 moles Br 79.90 g Br
--------------------- x ------------------------ = 119.85 grams Br or 120 grams Br (sig figs)
1 mole
5 electrons
Boron atomic number 5 has five electrons in its ground state.
Commonly Boron will lose 3 electrons leaving 2 electrons in its most common ionic form.
Explanation:
The atomic number gives the number of protons. Protons which have a positive charge are balanced by an equal number of electrons in a neutral atom.
Boron number 5 has five protons and therefore as a neutral atom also has five electrons.
Boron has an electron configuration of
1s22s22p1
The most stable electron configuration for Boron is
1s2
+ 3 charges. By losing three electrons Boron can achieve the stable electron structure of Helium
Brainliest? :D
