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2 years ago

A chess club with 80 members is electing a new president. Hans received 32 votes. What percentage of the members voted for Hans?

Mathematics

1 answer:

Lerok [7]2 years ago

7 0

Answer: 40%

Step-by-step explanation: To find what percentage of members voted for Hans simply multiply 32 by 100.

32 x 100 = 3200.

Then, divide that number, or 3200 by 80.

3200/80 = 40.

So, 40, or 40% of members voted for Hans.:)

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How do you multiply decimals?

Ulleksa [173]

I found this online, hope it helps

Just follow these steps:
Multiply normally, ignoring the decimal points.
Then put the decimal point in the answer - it will have as many decimal places as the two original numbers combined.

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2 years ago

100 PTS

Digiron [165]

Answer:

69 yards

Step-by-step explanation:

Perimeter = 2(length + width)

300 = 2(81 + width)

150 = 81 + width

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2 years ago

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Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.

Aleks [24]

Answer:

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

Step-by-step explanation:

The actual Series is::

$\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$

The method we are going to use is comparison method:

According to comparison method, we have:

$\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n$

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

$=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}$

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}$

Now:

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}$

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

$\sum_{n=1}^{inf}\frac{1}{n^p}$

if p>1 then series converges. In oue case we have:

$\sum_{n=1}^{inf}b_n=\frac{1}{n^4}$

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

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3 years ago

Each pack of batteries cost $21. How many i can buy if i have $63?

Rashid [163]

Each pack of batteries cost $21 each.
And then you have $63.

The operation to be used: Division.

63 ÷ 21 ==

Answer: 3

= You can buy 3 packs of batteries with your $63.

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3 years ago

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victus00 [196]

Answer:

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Step-by-step explanation:

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3 years ago

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