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maxonik [38]
3 years ago
11

I need help with #4... Chemistry is my worst subject.

Chemistry
1 answer:
ella [17]3 years ago
5 0
Use slader.com it helps with all textbook work!
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Now we need to find the amount of NF3 that can be formed by the complete reactions of each of the reactants. If all of the N2 wa
Alex777 [14]

The question is incomplete, the complete question is:

Nitrogen and fluorine react to form nitrogen fluoride according to the chemical equation:

N_2(g)+3F_2(g)\rightarrow 2NF_3(g)

A sample contains 19.3 g of N_2 is reacted with 19.3 g of F_2. Now we need to find the amount of NF_3 that can be formed by the complete reactions of each of the reactants.

If all of the N_2 was used up in the reaction, how many moles of NF_3 would be produced?

<u>Answer:</u> 1.378 moles of NF_3 are produced in the reaction.

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ......(1)

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

In the given chemical reaction, N_2 is considered as a limiting reagent because it limits the formation of the product and it was completely consumed in the reaction.

We are given:

Mass of N_2 = 19.3 g

Molar mass of N_2 = 28.02 g/mol

Putting values in equation 1:

\text{Moles of }N_2=\frac{19.3g}{28.02g/mol}=0.689mol

For the given chemical reaction:

N_2(g)+3F_2(g)\rightarrow 2NF_3(g)

By the stoichiometry of the reaction:

1 mole of N_2 produces 2 moles of NF_3

So, 0.689 moles of N_2 will produce = \frac{2}{1}\times 0.689=1.378mol of NF_3

Hence, 1.378 moles of NF_3 are produced in the reaction.

8 0
3 years ago
Mr. Aguilar has ice on his wrist, literally. If the ice on Mr. Aguilar’s wrist (H2O) weighs 546 grams, how many ice particles ar
Lunna [17]

Answer:

The answer to your question is  1.83 x 10²⁵ particles

Explanation:

Data

particles of H₂O = ?

mass of H₂O = 546 g

Process

1.- Calculate the molar mass of Water

Molar mass = (2 x 1) + (1 x 16)

                   = 2 + 16

                   = 18 g

2.- Use proportions to find the number of particles. Use Avogadro's number.

                 18 g ---------------- 6.023 x 10²³ particles

                546 g ---------------   x

                  x = (546 x 6.023 x 10²³) / 18

3.- Simplification

                  x = 3.289 x 10²⁶ / 18

4.- Result

                  x = 1.83 x 10²⁵ particles

6 0
3 years ago
If a gas has a molecular mass of 44.0, the volume of 88.0 grams of the gas at STP would be ..
Montano1993 [528]
2) 11.2
All you have to do is multiply 44 by 22.4 L, which equals 985.6
Then you divide 985.6 by 88 to get your answer of 11.2 L
3 0
2 years ago
List earth and the gas giant planets from the hottest to the coldest planet
inessss [21]

Answer:

1. Venus

471°C

2. Mercury

(430°C) during the day,  (-180°C) at night

3. Earth

16°C

4. Mars

-28°C

5. Jupiter

-108°C

6. Saturn

-138°C

7. Uranus

-195°C

8. Neptune

-201°C

Explanation:

.

8 0
1 year ago
HELP ASAP!! PLEASE !!
ZanzabumX [31]

Answer:

8,3, 7,7

Explanation:

6 0
2 years ago
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