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maxonik [38]
3 years ago
11

I need help with #4... Chemistry is my worst subject.

Chemistry
1 answer:
ella [17]3 years ago
5 0
Use slader.com it helps with all textbook work!
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Acetic acid (HC2H3O2) is the active ingredient in vinegar. Calculate the mass percent composition of O in acetic acid.
skelet666 [1.2K]

Answer:

53.29% of acetic acid is Oxygen

Explanation:

Step 1: Given data

Acetic acid it's molecular formula is HC2H3O2. This means it consists of 3 elements Carbon, Hydrogen and oxygen.

Step 2: the molar masses

The molecular mass of acetic acid is:

4* H = 4* 1.01 g/mole

2* C = 2*12 g/mole

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32 g of the 60.052 g is Oxygen

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53.29% of acetic acid is Oxygen.

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3 years ago
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Hope this helps :D

4 0
3 years ago
If 0.5 mole of zn is added to hydrochloric acid containing 0.6 mol of hcl, which reactant is in excess
ser-zykov [4K]
The balanced equation for the reaction is as follows;
Zn + 2HCl --> ZnCl₂ + H₂
stoichiometry of Zn to HCl is 1:2
limiting reagent is the reactant that is fully consumed in the reaction.
the amount of product formed depends on amount of limiting reactant present.
The excess reactant is when it has been provided in excess and only a fraction of the provided amount is used up in the reaction.
Amount of Zn moles - 0.5 mol
Amount of HCl moles - 0.6 mol
If Zn is provided, number of HCl moles reacted - 0.5 x 2 = 1.0 mol of HCl is required, but only 0.6 mol of HCl is provided.
HCl is therefore the limiting reactant, 
Number of Zn moles required - 0.6 mol /2 = 0.3 mol
But 0.5 mol are given, therefore 0.2 mol of Zn is in excess
6 0
3 years ago
3. There are about 7 billion (7.0x10') people on earth. If we divided the dollar amount from
Harman [31]

Answer: i dont know it

Explanation:

6 0
3 years ago
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