Look at the figure. If <1=<2 describe the relationship between lines a and b

The radius of the large sphere is double the radius of the small sphere. How many times does the volume of the large sphere than

pshichka [43]

Answer:

8 times larger.

Step-by-step explanation:

The radius of the large sphere is double the radius of the small sphere.

Question asked:

How many times does the volume of the large sphere than the small sphere

Solution:

Let radius of the small sphere =  $x$ 

As the radius of the large sphere is double the radius of the small sphere:

Then, radius of the large sphere = $2x$

To find that how many times is the volume of the large sphere than the small sphere, we will divide the volume of large sphere by volume of small sphere:-

For smaller sphere: $Radius = x$

$Volume \ of \ sphere = \frac{4}{3} \pi r^{3}$

$=\frac{4}{3} \pi x^{3}$

For larger sphere: $Radius = 2x$

$Volume \ of \ sphere = \frac{4}{3} \pi r^{3}$

$=\frac{4}{3} \pi (2x)^{3}$

Now, we will divide volume of the larger by the smaller one:

$=\frac{4}{3} \pi (2x)^{3}\div\frac{4}{3} \times\frac{\pi }{1 } \times x^{3}\\ \\ =\frac{4}{3} \pi\times8x^{3} \times\frac{3}{4\pi }\ \times\frac{1}{x^{3} }$

$\frac{4}{3}\pi\ is \ canceled\ by\ \frac{3}{4\pi } \ and\ also\ x^{3} is\ canceled\ by \ \frac{1}{x^{3} }$

Now, we have

= $\frac{8}{1}$

Therefore, the volume of the large sphere is 8 times larger than the smaller sphere.

7 0

3 years ago

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Solve the expressions on the left when x=5 3x-10 x^2-15 5x-21 x+10-8

Nitella [24]

Answer:

5

10

4

7

Step-by-step explanation:

Apply the value of x into the expressions:

3(5) - 10 = 15 - 10

= 5

5² - 15 = 25 - 15

= 10

5(5) - 21 = 25 - 21

= 4

5 + 10 - 8 = 15 - 8

= 7

5 0

3 years ago

Read 2 more answers

H=vt+1/2gt^2 solving for G GIVING BRAINLISEST

ololo11 [35]

Answer:

$g=\frac{2h}{t^2}-\frac{2v}{t}$

Step-by-step explanation:

So we have the equation:

$h=vt+\frac{1}{2}gt^2$

And we want to solve for g.

First, isolate g. To do so, subtract vt from both sides:

$h-vt=\frac{1}{2}gt^2$

Multiply both sides by 2:

$2h-2vt=gt^2$

Now, divide both sides by t^2:

$g=\frac{2h-2vt}{t^2}$

Expand:

$g=\frac{2h}{t^2}-\frac{2vt}{t^2}$

Simplify the second term:

$g=\frac{2h}{t^2}-\frac{2v}{t}$

And we're done!

8 0

3 years ago

Read 2 more answers

Given a quadrilateral with vertices ????(0, 5), ????(6, 5), ????(4, 0), and H(−2, 0):

tankabanditka [31]

cant help when you put question marks!

please do this better!

8 0

3 years ago

Please help. Thank you!

Makovka662 [10]

Answer: See explanation

Step-by-step explanation:

By the Triangle Inequality Theorem, the length of the side must be greater than 1 ft because the sum of two side lengths must be greater than the length of the third side. The third side must be less than 7 ft but greater than 1 ft.

Triangle inequality: 1 < x < 7

Hope that helped!

3 0

3 years ago