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3 years ago

Pls try to understand my doubt and clear it .

Physics

1 answer:

jeka943 years ago

7 0

I can’t read the last few numbers, is that an 8 ??

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4 years ago

Holding onto a tow rope moving parallel to a frictionless ski slope, a 70.1 kg skier is pulled up the slope, which is at an angl

lara [203]

Answer:

given,

mass of the skier = 70.1 Kg

angle with horizontal, θ = 8.6°

magnitude of the force,F = ?

a) Applying newton's second law

$m g sin\theta - F_{rope} = ma$

velocity is constant, a = 0

$m g sin\theta - F_{rope} =0$

$F_{rope} = m g sin\theta$

$F_{rope} = 70.1\times 9.8\times sin 8.6^0$

$F_{rope}= 102.73\ N$

b) now, when acceleration, a = 0.135 m/s²

$F_{rope}-m g sin\theta = ma$

velocity is constant, a = 0.135 m/s₂

$F_{rope} = m g sin\theta+ma$

$F_{rope} = 70.1\times 9.8\times sin 8.6^0+70.1\times 0.135$

$F_{rope}= 112.19\ N$

7 0

4 years ago

A charge of 8 nC is placed uniformly on a square sheet of nonconducting material of side 22 cm in the yz plane.(d) What is the m

mr_godi [17]

This is a problem dealing with the surface charge density. Based on the given problem above, <span>your charge is 8nc on a square plate of 22 cm x22 cm given that E= (surface charge density)/2ε₀ so answer would be 8nc/22/22/2ε₀. Therefore, the magnitude of the electric field to the right (x>0) of the right face of the slab would be </span>8nc/22/22/2ε₀.

5 0

4 years ago

Read 2 more answers

A 2.7-kg cart is rolling along a frictionless, horizontal track towards a 1.1-kg cart that is held initially at rest. The carts

olga2289 [7]

Answer:

Part a)

P = 8.23 kg m/s

Part b)

v = 3.05 m/s

Explanation:

Part a)

momentum of cart 1 is given as

$P_1 = m_1v_1$

$P_1 = (2.7)(3.7) = 9.99 kg m/s$

Momentum of cart 2 is given as

$P_2 = m_2v_2$

$P_2 = (1.1)(-1.6) = -1.76 kg m/s$

Now total momentum of both carts is given as

$P = P_1 + P_2$

$P = 8.23 kg m/s$

Part b)

Since two carts are moving towards each other due to mutual attraction force and there is no external force on two carts so here momentum is always conserved

so here we will have

$P_i = P_f$