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2 years ago

A bag contains 30 lottery balls numbered 1-30. A ball is selected, replaced, then another is drawn. Find each probability.

Mathematics

1 answer:

swat322 years ago

3 0

Answer:

17÷3 ok so it was just a compliment sometime soon

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The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0

3 years ago

Which equation has the solution n = 11?

kap26 [50]

Answer:

3n + 12 = 45

Step-by-step explanation:

3n + 12 = 45

3n = 45 - 12

3n = 33

n = <u>3</u><u>3</u>

n = 11

4 0

3 years ago

Read 2 more answers

Answer 4 and 5 pleaseeeeeeeeee

rusak2 [61]

4.)
To solve for Y it is To solve for X
-8y=-6x -8y=-6x
/-8 /-8 /-6 /-6

y=3/4(x) 4/3(y)=x

5.)
to solve for Y To solve for X
1/2(y)=4(2x-1/4) 1/2(y)=4(2x-1/4)
1/2(y)=8x-1 /4 /4
*2 *2 y/8=2x-1/4
+1/4 +1/4
y=16x-2 (y/8)+1/4=2x
/2 /2

((y/8)+1/4)/2=x

5 0

2 years ago

In a survey of 3,500 people who owned a certain type of car, 2,100 said they would buy that type of car again. What percent of

PSYCHO15rus [73]

Answer:

60%

Part=Percent • whole

2100=m•3500

2100/3500 = 3/5

3/5 • 20/20 = 60/100 = 60%

6 0

2 years ago

What is the simplified form of the fraction below 14/49

sineoko [7]

Answer:

That would be 2/7.

Step-by-step explanation:

By finding the GCD between 14 and 49, you can reduce the fraction.

The GCD between 14 and 49 is 7.

By dividing both 14 and 49 by 7, you'll reduce your answer.

14/49 ---> 2/7

6 0

1 year ago

Read 2 more answers