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Anit [1.1K]
3 years ago
8

PLEASE HELP!!

Chemistry
1 answer:
Mandarinka [93]3 years ago
8 0

Answer:

a. 211.7

Explanation:

Iron Pyrite reacts with Oxygen to produce Iron (II) Oxide and Sulphur (IV) Oxide.

The equation is as follows:

4FeS₂₍s₎ + 11O₂₍g₎ → 2Fe₂O₃₍s₎ + 8SO₂₍g₎

From the equation, 4 moles of FeS₂ produce 8 moles of SO₂.

Therefore the reaction ratio is 4:8 or 1:2

198.20 grams of FeS₂ into moles is calculated as follows:

Moles= Mass/RMM

RMM of FeS₂ is 119.9750g/mol.

Number of moles = 198.20/119.9750g/mol

=1.652 moles of FeS₂

The reaction ratio of FeS₂ to SO₂ produced is 1:2

Thus SO₂ produced = 1.652 moles×2/1=3.304 moles

The mass of SO₂ produced =Moles ×RMM

=3.304 moles ×64.0638 g/mol

=211.667 grams

=211.7g

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If the K a Ka of a monoprotic weak acid is 7.3 × 10 − 6 , 7.3×10−6, what is the pH pH of a 0.40 M 0.40 M solution of this acid?
olga_2 [115]

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Explanation:

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HA + H₂O   ⇄ H₃O⁺ + A⁻    with  Ka = [ H₃O⁺] x [A⁻]/ [HA]

The pH is the negative log of the H₃O⁺ concentration, we know the equilibrium constant, Ka and the original acid concentration. So we will need to find the [H₃O⁺] to solve this question.

In order to do that lets set up the ICE table helper which accounts for the species at equilibrium:

                          HA                                   H₃O⁺                          A⁻          

Initial, M             0.40                                   0                              0

Change , M          -x                                     +x                            +x

Equilibrium, M    0.40 - x                              x                               x

Lets express these concentrations in terms of the equilibrium constant:

Ka = x² / (0.40 - x )

Now the equilibrium constant is so small ( very little dissociation of HA ) that is safe to approximate 0.40 - x to 0.40,

7.3 x 10⁻⁶ = x² / 0.40  ⇒ x = √( 7.3 x 10⁻⁶ x 0.40 ) = 1.71 x 10⁻³

[H₃O⁺] = 1.71 x 10⁻³

Indeed 1.71 x 10⁻³ is small compared to 0.40 (0.4 %). To be a good approximation our value should be less or equal to 5 %.

pH = - log ( 1.71 x 10⁻³ ) = 3.8

Note: when the aprroximation is greater than 5 % we will need to solve the resulting quadratic equation.

4 0
3 years ago
What mass of sodium chloride contains 4.59 x 10 24 formula units?
shtirl [24]
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Then, what you are looking for is the mass in 4.59*10^24  molecules.

The procedure involves to convert the 4.59 * 10^24 molecules into moles and use the molar mass of the sodium chloride.

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3) mass of NaCl = molar mass *  number of moles = 58.44 g/mol * 7.62 mol = 445.31 g of NaCl

Answer: 445.31 g of NaCl.

 
7 0
2 years ago
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