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mihalych1998 [28]
4 years ago
7

Why is it important that acids and bases have certain naming rules? Why shouldn't we just call them whatever we want?​

Chemistry
2 answers:
DanielleElmas [232]4 years ago
7 0

Explanation:

This naming can help identify a solution as acid or base (and some of its properties) even before conducting tests. It also allows scientists across the world to collaborate through using a standard naming system.

Naming of the acids and bases is significant in identifying the type and properties of the acid or base. Acids, for example, are named based on the anion attached to the H+ ion in the chemical structure. For example, HCl is called hydrochloric acid because the H+ is bound to a Chloride ion. The suffix for acid is;  –ic, -ate & -ous.

Bases, on the other hand, are named based on the cation attached to the hydroxide eg, CaOH is named calcium hydroxide. The suffix for bases is -ide.

maks197457 [2]4 years ago
6 0

Answer:

<em>It is important to have certain naming rules for both acids or bases so we can distinguish them from one another. </em>

Explanation:

These scientific names are used all over the world. Without these rules, one would not be able to tell the difference between an acid or base. These names not only explain the nature of these substances as well as their reactive properties.  

<u>The name of an acid is classified on the basis of its anions while a base is named using the ionic system. </u>

The examples  of common bases are <em>potassium hydroxide, sodium hydroxide </em>etc while common acids are <em>sulfuric acid, citric acid</em> etc.

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Answer:

The balanced half-reaction for the reduction of dichromate ion to chromium ion in acidic aqueous solution:

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Explanation:

The reaction :

Cr_2O_7^{2-}\rightarrow Cr^{3+}

Balancing of reaction in an acidic medium:

Step 1: Balance the atoms in the reaction:

Cr_2O_7^{2-}(aq)\rightarrow 2Cr^{3+}(aq)

Step 2: Balance oxygen atom by adding water on the side where no oxygen or less oxygen atom is present;

Cr_2O_7^{2-}(aq)\rightarrow 2Cr^{3+}(aq)+7H_2O(l)

Step 3: Balance the hydrogen atom by adding  hydrogen ions on the side where water is absent:

Cr_2O_7^{2-}(aq)+14H^+(aq)\rightarrow 2Cr^{3+}(aq)+7H_2O(l)

Step 4: Now balance charge by adding electrons on the side where more positive charge is present

Cr_2O_7^{2-}(aq)+14H^+(aq)+6e^-\rightarrow 2Cr^{3+}(aq)+7H_2O(l)

The balanced half-reaction for the reduction of dichromate ion to chromium ion in acidic aqueous solution:

Cr_2O_7^{2-}(aq)+14H^+(aq)+6e^-\rightarrow 2Cr^{3+}(aq)+7H_2O(l)

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There are two atoms: A and B. Atom A has 7 electrons and atom B has 13 electrons. which of the following is TRUE
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The statement which is true about <em>Atom A</em> and <em>Atom B</em> is; Choice B: <em>Atom B will give up electrons to form bonds.</em>

According to the question;

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For atom B:

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Since, electrons need 8 electrons to assume a full octet;

Consequently, Atom B will give up electrons to become stable.

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37.2 liters of a gas has a pressure of 362.43 kPa at 46.5 °C. If the pressure increases to
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Answer:

Option A. 25.7 L.

Explanation:

Step 1:

Data obtained from the question. This include the following:

Initial volume (V1) = 37.2 L

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Final temperature (T2) = 149.2 °C

Final volume (V2) =.?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

This can be achieved as shown below:

Temperature (K) = Temperature (°C) + 273

T (K) = T (°C) + 273

Initial temperature (T1) = 46.5 °C

Initial temperature (T1) = 46.5 °C + 273 = 319.5 K.

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Final temperature (T2) = 149.2 °C + 273 = 422.2 K.

Step 3:

Determination of the new volume.

This can be obtained by using the general gas equation as shown below:

Initial volume (V1) = 37.2 L

Initial pressure (P1) = 362.43 kPa

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Final pressure (P2) = 693.9 kPa

Final temperature (T2) = 422.2 K

Final volume (V2) =.?

P1V1/T1 = P2V2/T2

362.43×37.2/319.5 = 693.9 × V2/422.2

Cross multiply

319.5×693.9×V2 = 362.43×37.2×422.2

Divide both side by 319.5 × 693.9

V2 = (362.43×37.2×422.2)/(319.5×693.9)

V2 = 25.7 L

Therefore, the new volume is 25.7 L.

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