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Anestetic [448]
3 years ago
5

Which answer below correctly identifies the type of change and the explanation when magnesium comes into contact with hydrochlor

ic acid?
physical change because no color change occurred

physical change because the observation of a gas forming is evidence of a state change, which is
reversible

chemical change because a temperature change occurred, a solid disappeared, and a gas was
produced

chemical change because two substances were mixed, which always results in the formation of a
new substance
Chemistry
2 answers:
Oliga [24]3 years ago
5 0

Answer:

A chemical change because a temperature change occurred, the solid disappeared and a gas was produces

Explanation:

Magnesium reacts with hydrochloric acid releasing energy, and leading to the formation of  magnesium chloride and hydrogen gas. This is represented by the equation below:

Mg₍s₎ + 2HCl₍aq)⇒ MgCl₂₍aq₎ + H₂₍g₎

Semenov [28]3 years ago
3 0

Answer:

chemical change because a temperature change occurred, a solid disappeared, and a gas was  produced

Explanation:

In a chemical change there is a change in the chemical property of the reactant such that a new product is formed such as rusting of iron to form iron oxide. In a physical change there is phase change of the substance such as melting of ice.  

Mg is a metal that combines with the acid HCl to form the salt magnesium chloride, MgCl₂ and hydrogen gas, H₂. The chemical property of salts and gases are completely different from that of metal and acids.  

Mg + HCl = MgCl₂ + H₂  

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2 years ago
Which of the following characteristics do all unicellular organisms share?
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3 0
3 years ago
A sample of 28 Mg decays initially at a rate of 53500 disintegrations per minute, but the decay rate falls to 10980 disintegrati
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Answer : The half life of 28-Mg in hours is, 6.94

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant

t = time passed by the sample = 48.0 hr

a = initial amount of the reactant disintegrate = 53500

a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520

Now put all the given values in above equation, we get

k=\frac{2.303}{48.0}\log\frac{53500}{42520}

k=9.98\times 10^{-2}hr^{-1}

Now we have to calculate the half-life.

k=\frac{0.693}{t_{1/2}}

9.98\times 10^{-2}=\frac{0.693}{t_{1/2}}

t_{1/2}=6.94hr

Therefore, the half life of 28-Mg in hours is, 6.94

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