Answer : The radii of the two ions Cl⁻ ion and Na⁺ ion is, 181 and 102 pm respectively.
Explanation :
As we are given that the Na⁺ radius is 56.4% of the Cl⁻ radius.
Let us assume that the radius of Cl⁻ be, (x) pm
So, the radius of Na⁺ = 
In the crystal structure of NaCl, 2 Cl⁻ ions present at the corner and 1 Na⁺ ion present at the edge of lattice.
Thus, the edge length is equal to the sum of 2 radius of Cl⁻ ion and 2 radius of Na⁺ ion.
Given:
Distance between Na⁺ nuclei = 566 pm
Thus, the relation will be:





The radius of Cl⁻ ion = (x) pm = 181 pm
The radius of Na⁺ ion = (0.564x) pm = (0.564 × 181) pm =102.084 pm ≈ 102 pm
Thus, the radii of the two ions Cl⁻ ion and Na⁺ ion is, 181 and 102 pm respectively.
Answer: kg= 0.37
Explanation:
Use the molality formula.
M= m/kg
<u>Answer:</u> The molarity of HCl solution is 0.262 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:

We are given:
Given mass of HCl = 0.3366 g
Molar mass of HCl = 36.5 g/mol
Volume of the solution = 35.23 mL
Putting values in above equation, we get:

Hence, the molarity of HCl solution is 0.262 M.
The answer is d hope this helps