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Zolol [24]
3 years ago
8

Which subatomic particles orbit the nucleus

Chemistry
2 answers:
Julli [10]3 years ago
5 0
Electrons are that sub-atomic particles
Masja [62]3 years ago
3 0
The answer is electrons

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In any atom, the size of the nucleus with respect to the size of
iragen [17]

Answer:

Size of the nucleus of an atom is very small as compared to the size of the atom.

According to Rutherford gold foil experiment, nucleus is very small in size as compared to the size of the atom as a whole. Nucleus is very hard, dense and positively charged which consists of protons and neutrons.

Explanation:

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3 years ago
The Statue of Liberty is composed of copper. The smallest particle of any amount of copper is A) an atom. B) an element. C) a co
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an atom because its the smallest thing in the entire world and in all orgnaisms

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2 years ago
When you light a fire place what energy transformation takes place
DedPeter [7]
Heat energy is released to warm the house
3 0
3 years ago
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A stock phenolphthalein solution was prepared by dissolving 0.050 g in a total volume of 100.0 ml. You place one drop (0.050 ml)
devlian [24]

Answer:

the value of molar absorptivity is 229000 M^{-1} cm^{-1}

Explanation:

given data

phenol phthalein solution = 0.050 g

total volume = 100.0 ml

dilute = 100.0 ml

diluted sample = 0.18

solution

we get here concentration that is express as

concentration = ( mass of solute × 1000 ) ÷ ( molar mass of solute × volume of solution ) .............1

put here value

concentration = \frac{0.050\times 1000}{318.32\times 100}    

concentration = 0.00157 M

and here dillution equation is express as

c1 × v1 = c2 × v2   .................2

here c1 and c2 is initial and final concentration

and v1 and v2 is initial and final volume

put here value  

0.001571 × 0.050 = c2 × 100

c2 = 7.855 × 10^{-7} M

and

now we get molar by absorbance equation that is

A = E × C ×  l   ................3

here A is absorbance and E is molar and c is absorptivity and l is path length

put here value

0.18 = E × 7.855 × 10^{-7}  × 1

E = 229000 M^{-1} cm^{-1}

3 0
3 years ago
Lead has a density of 11.3 g/cm3. if you have 1.0 kg of lead, what is the volume in cubic centimeters (cm3)? remember to select
Novosadov [1.4K]
In this case, you are given the density( 11.3g/cm3) and the weight (1kg) of the lead. You are asked to find the volume of the lead.
To find volume you need to divide the weight with the density. It would be:
volume= weight/density
volume = 1kg x (1000 gram/kg) / (11.3g/cm3)= 88.495 cm3

4 0
3 years ago
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