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katovenus [111]
3 years ago
8

An echo is not heard in a small room.why ? give reason​

Physics
2 answers:
JulsSmile [24]3 years ago
7 0

Answer:

They can't hear an echo in small room because in it the sound can't be reflected back. For an echo of a sound to be heard,the minimum distance between the source of sound and the walls of the room should be 17.2 m.

hopw it helps

Stella [2.4K]3 years ago
7 0
The room is too small it has to be ag least 17.2 meters for the noise to bounce
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Which unit of heat was originally defined in terms of the Fahrenheit temperature scale, not the Celsius scale?
Kitty [74]

Answer:

I think the answer would be British Thermal Unit

Explanation:

It equals one degree Fahrenheit and the equation for it is  1.055 × 103 joules.

8 0
3 years ago
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When the forces acting moving body are balanced the net force becomes zero. As a result the body will:
WINSTONCH [101]

Answer:

<h2>a</h2><h2> move with an increasing velocity</h2>
5 0
3 years ago
A 35.0-cm-diameter circular loop is rotated in a uniform electric field until the position of maximum electric flux is found. Th
MAVERICK [17]

To solve this problem we will apply the concept of Electric Flow, which is understood as the product between the Area and the electric field. For the data defined by the area, we will use the geometric measurement of the area in a circle (By the characteristics of the object) This area will be equivalent to,

\phi = 35 cm

r = 17.5 cm = 0.175 m

A = \pi r^2 = \pi (0.175)^2 = 0.09621m^2

Applying the concept of electric flow we have to

\Phi = EA

Replacing,

5.42*10^5N \cdot m^2/C = E (0.09621m^2)

E = 5.6335*10^6N/C

Therefore the magnitude of the electric field is 5.6335*10^6N/C

7 0
3 years ago
he fan blades on a jet engine make one thousand revolutions in a time of 54.9 ms. What is the angular frequency of the blades?
Gnesinka [82]

So, the angular frequency of the blades approximately <u>36.43π rad/s</u>.

<h3>Introduction</h3>

Hi ! Here I will discuss about the angular frequency or what is also often called the angular velocity because it has the same unit dimensions. <u>Angular frequency occurs, when an object vibrates (either moving harmoniously / oscillating or moving in a circle)</u>. Angular frequency can be roughly interpreted as the magnitude of the change in angle (in units of rad) per unit time. So, based on this understanding, the angular frequency can be calculated using the equation :

\boxed{\sf{\bold{\omega = \frac{\theta}{t}}}}

With the following condition :

  • \sf{\omega} = angular frequency (rad/s)
  • \sf{\theta} = change of angle value (rad)
  • t = interval of the time (s)

<h3>Problem Solving</h3>

We know that :

  • \sf{\theta} = change of angle value = 1,000 revolution = 1,000 × 2π rad = 2,000π rad/s >> Remember 1 rev = 2π rad/s.
  • t = interval of the time = 54.9 s.

What was asked :

  • \sf{\omega} = angular frequency = ... rad/s

Step by step :

\sf{\omega = \frac{\theta}{t}}

\sf{\omega = \frac{2,000 \pi}{54.9}}

\boxed{\sf{\omega \approx 36.43 \pi \: rad/s}}

<h3>Conclusion :</h3>

So, the angular frequency of the blades approximately 36.43π rad/s.

8 0
2 years ago
Need quite a bit of help
Gnom [1K]

When the cart was at Table

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Now acceleration due to gravity acting on the gravity.

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Hence.

\\ \sf\Rrightarrow F_{net}=0N

  • So the cart doesn't move
3 0
3 years ago
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