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marusya05 [52]
3 years ago
7

4. What happens to energy during the formation of a solution?

Physics
1 answer:
Svetlanka [38]3 years ago
6 0

D It is released or absorbed.

Explanation:

To form a solution, energy is absorbed or released in the process.

A solution is a substance made up of solute dissolved in a solvent. The solute is the dissolved substance where as the solvent is the dissolving medium.

  • To form a solution, solutes are dissolved.
  • In this dissolution reaction, energy is used to break bonds within the solute to bring them in contact with the solvent.
  • The combination of the solute with the solvent is a bond formation process.
  • Bond formation is an exothermic process in which energy is released.
  • Bond breaking process is endothermic in which energy is absorbed.
  • To form solutions, bonds are formed and broken.

Learn more:

Solutions brainly.com/question/8781174

#learnwithBrainly

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Roger drives his car at a constant speed of 80 km/hr. How far can he travel in 2 hrs. and 30 minutes?
bonufazy [111]

Answer:

200 km/hr

Explanation:

Since he goes 80km per hour, multiply this by 2.5 or two and a half hours.

80 x 2.5 = 200 km/hr.

6 0
2 years ago
Instructions:Select the correct answer from the drop-down menu. The Longmenshan Fault is in China. This fault was created when t
lina2011 [118]
I say Reverse Fault, Hope this helps :)
3 0
3 years ago
a 3520 kg truck moving north at 18.5 m/s makes an INELASTIC collision with an 1480 kg car moving east after colliding they have
anyanavicka [17]

Answer:

Explanation:

An inelastic collision is one where 2 masses collide and stick together, moving as a single mass after the collision occurs. When we talk about this type of momentum conservation, the momentum is conserved always, but the kinetic momentum is not (the velocity changes when they collide). Because there is direction involved here, we use vector addition. The picture before the collision has the truck at a mass of 3520 kg moving north at a velocity of 18.5. The truck's momentum, then, is 3520(18.5) = 65100 kgm/s; coming at this truck is a car of mass 1480 kg traveling east at an unknown velocity. The car's momentum, then, is 1480v. The resulting vector (found when you pick up the car vector and stick the initial end of it to the terminal end of the truck's momentum vector) forms the hypotenuse of a right triangle where one leg is 65100 kgm/s, and the other leg is 1480v. Since we already know the final velocity of the 2 masses after the collision, we can use that to find the final momentum, which will serve as the resultant momentum vector in our equation (we'll get there in a sec). The final momentum of this collision is

p = mv and

p = (3520 + 1480)(13.6) so

p = 68000. Final momentum. The equation for this is a take-off of Pythagorean's Theorem and the one used to find the final magnitude of a resultant vector when you first began your vector math in physics. The equation is

p_f=\sqrt{(p_{truck})^2+(p_{car})^2} which, in words, is

the final momentum after the collision is equal to the square root of the truck's momentum squared plus the car's momentum squared. Filling in:

68000=\sqrt{(65100)^2+(1480v)^2} and

(68000)^2=(65100)^2+(1480v)^2 and

4624000000=4238010000+2190400v^2  and

385990000=2190400v^2 and

176.2189554=v^2 so

v = 13.3 m/s at 72.6°

6 0
3 years ago
Suppose a wheel with a tire mounted on it is rotating at the constant rate of 3.37 times a second. A tack is stuck in the tire a
zhannawk [14.2K]

Answer:

The tangential speed of the tack is 8.19 m/s.

Explanation:

The wheel rotates 3.37 times a second that means wheel complete 3.37 revolutions in a second. Therefore, the angular speed ω of the wheel is given as follows:

\omega =3.37rev/s \times(\frac{2\pi rad}{1s} )\\\\=21.174rad/s

Use the relation of angular speed with tangential speed to find the tangential speed of the tack.

The tangential speed v of the tack is given by following expression

v = ω r

Here, r is the distance to the tack from axis of rotation.

Substitute 21.174 rad/s for ω, and 0.387 m for r in the above equation to solve for v.

v = 21.174 × 0.387

v = 8.19m/s

Thus, The tangential speed of the tack is 8.19 m/s.

4 0
3 years ago
Read 2 more answers
1. Boyle's law relates the pressure of a gas to its
KIM [24]

Answer:

volume is the correct answer

Explanation:

7 0
2 years ago
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