Mass of H₂ needed to react with O₂ : 1.092 g
<h3>Further explanation</h3>
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
Reaction
O₂(g) + 2H₂(g) → 2H₂O(g)
mass of O₂ : 8.75 g
mol O₂(MW=32 g/mol) :
From the equation, mol ratio of O₂ : H₂ = 1 : 2, so mol H₂ :
Mass H₂ (MW=2 g/mol) :
Answer:
972.3 Torr
Explanation:
P2=P1V1/V2
You can check this by knowing that P and V at constant T have an an inverse relationship. Hence, this is correct.
Mol sulfuric acid = 19 g * (1 mol) / (98.1 g) = 0.19367 mol
mol H2O = 0.19367 mol H2SO4 * (2 H2O) / (1 H2SO4)
= 0.387359 mol H2O
grams H2O = 0.387359 mol H2O * (18 g)/(1 mol)
= 6.97 g
The answer is 7.0 grams of water
Answer: The volume occupied by 2.50 moles of 
gas at STP is 56.0L
Explanation:
According to ideal gas equation:
P = pressure of gas = 1 atm (at STP)
V = Volume of gas = ?
n = number of moles = 2.50
R = gas constant =
T =temperature =
(at STP)
Thus the volume occupied by 2.50 moles of gas at STP is 56.0L
