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aev [14]
3 years ago
5

Rod cells work best in dim light and enable you to see black, white, and shades of gray.

Chemistry
1 answer:
Ivenika [448]3 years ago
7 0
Answer:
True rod cell are best in the dark or dim light.
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During an exothermic reaction, ΔH for the reactants was 890 kJ/mol. Which of the following statements is correct about the ΔH fo
kaheart [24]

Answer:-A. It is less than 890 kJ/mol because the amount of energy required to break bonds is less than the amount of energy released in forming bonds.

Explanation: Endothermic reactions are defined as the reactions in which energy of the product is greater than the energy of the reactants. The total energy is absorbed in the form of heat and \Delta H for the reaction comes out to be positive.

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and \Delta H for the reaction comes out to be negative.

In the formation of new bonds more energy is released than is required to break the existing bonds, heat is released.

In the formation of bonds less energy is released than is required to break the existing bonds, heat is absorbed.

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3 years ago
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Help ASAP 40 pts If answer 6
Olenka [21]

Answer:

1. B

2. C.

3. C

4. C.

5. A

6. B

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What reaction will take place if h2o is added to a mixture of nanh2/nh3? draw the products of the reaction (without sodium ion)?
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When sodium amide i.e.NaNH_{2} reacts with water i.e. H_{2}O results in the formation of sodium hydroxide i.e. NaOH and ammonia NH_{3}.

The chemical reaction is given by:

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Now, when ammonia i.e.NH_{3} reacts with water results in the formation of ammonium hydroxide i.e. NH_{4}OH

The chemical reaction is given by:

NH_{3}+H_{2}O\rightarrow NH_4OH

Thus, the products of the above reactions are ammonia and ammonium hydroxide (without sodium ion).

The structures of the products are shown in figure (1): ammonium hydroxide and figure (2) ammonia.


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The answer is Na-F. The F has highest electronegativity among these elements. So we need to find the element with smallest electronegativity. And this element is Na.
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