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aev [14]
3 years ago
5

Rod cells work best in dim light and enable you to see black, white, and shades of gray.

Chemistry
1 answer:
Ivenika [448]3 years ago
7 0
Answer:
True rod cell are best in the dark or dim light.
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What commercially available compound is used to generate cl2?
GuDViN [60]
<span>Bleach and ammonia can be used to make cl2. Bleach is commercially available and so people should be very careful during these experiments or even when mixing things in the household.</span>
6 0
3 years ago
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Water provides the ....................... for many plants and animals.
stepan [7]

Answer:

I would say the living for many plants and animals

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2 years ago
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How many moles of nitrogen gas are there in 6.8 liters at standard temperature and pressure (273 K and 100 kPa)?
Vika [28.1K]

Answer:-

0.3 moles

Explanation:-

According to the question,

Volume of nitrogen gas V = 6.8 litres.

Pressure of nitrogen gas P = 100 kPa.

Temperature of nitrogen gas T = 273 K.

We know the value of universal gas constant R = 8.314 litres kPa K−1 mol−1

Using the relation

PV = nRT

We have Number of moles of nitrogen gas n = P V / RT

= 100 kPa x 6.8 litres / ( 8.314 litres kPa K−1 mol−1 x 273 K)

= 0.3 mol

Thus there are 0.3 moles of nitrogen gas in 6.8 liters at standard temperature and pressure (273 K and 100 kPa)

7 0
3 years ago
Calculate the pH during the titration of 20.00 mL of 0.1000 M trimethylamine, (CH3)3N(aq), with 0.2000 M HClO4(aq) after 9.48 mL
balandron [24]

Complete Question

Calculate the pH during the titration of 20.00 mL of 0.1000 M trimethylamine, (CH3)3N(aq), with 0.2000 M HClO4(aq) after 9.48 mL of the acid have been added.Kb of trimethylamine = 6.5 x 10-5.

Answer:

The pH is  pH  =  9.84  

Explanation:

From  the question we are told that

   The  volume of trimethylamine, (CH3)3N(aq) is V_{t} = 20.00mL

    The concentration of trimethylamine is C_t =  0.1000 \  M  

    The  volume of HClO4(aq) is V_{h} = 9.48 mL

    The  concentration of  HClO4(aq) is  C_h  =  0.200 M

      The Kb  value is  K_b  =  6.5 * 10^{-5}

Generally the the pOH of this reaction is mathematically represented as

       pOH  =  pK_b + log [\frac{N_h}{N_b} ]

Here N_h is the number of moles of acid which is evaluated as

      N_h  = C_h  * V_h

=>    N_h  = 0.200  * 9.48

=>    N_h  = 1.896

Here N_t is the number of moles of acid which is evaluated as

      N_t  = C_t  * V_t

=>    N_t  = 0.100  * 20

=>    N_t  = 2

So

     pOH  =  -log(K_b) + log [\frac{N_h}{N_b} ]

     pOH  =  -log(6.5*10^{-5}) + log [\frac{1.896}{2} ]

=>   pOH  = 4.1639

Generally the pH is mathematically represented as

       pH  =  14 - pOH

=>    pH  =  14 - 4.1639  

=>    pH  =  9.84  

       

8 0
3 years ago
How many mole of copper, Cu are in 3.22 g of copper?​
Zolol [24]

Answer:

63.546

Explanation: Molecular weight of copper or mol The molecular formula for copper is Cu, The SI base unit for amount of substance is the mole

3 0
3 years ago
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