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Gnoma [55]
2 years ago
7

A steel fork and a plastic spoon are both at the same temperature. The fork feels colder when you touch it. This is because:

Physics
2 answers:
Debora [2.8K]2 years ago
8 0

Answer: The fork feels colder when you touch it because Steel conducts thermal energy better than plastic. The correct statement is 1

Explanation:

The ability of a material to transfer heat energy in an environment is known as thermal conductivity. It feels cooler to touch a steel spoon than a plastic spoon found in the same temperature because steel which is a type of metal is a highly efficient thermal conductor than spoon which is a plastic.

Metals can be defined as those substances which forms positive ion in a chemical reaction by lossing it's electrons. It has the following properties:

--> it is solid at room temperature

--> it has high melting point

--> it has high boiling point and

--> it is malleable.

Metals are said to be good thermal conductor because they contain free flowing conduction electrons. Therefore, when you touch a steel spoon and plastic spoon, it feels cooler because the steel metal is able to conduct heat away from your hand faster than the plastic which is a poor conductor of heat.

Margaret [11]2 years ago
3 0

Answer:

1. Steel conducts thermal energy better than plastic.

Explanation:

Both objects are at the same temperature, and when you touch them, you feel the steel to be colder.

This happens because steel is a better thermal conductor, then when you touch it, it "steals" more thermal energy from you than the plastic.

As the amount of thermal energy transmitted is greater for the steel, you will feel it to be colder.

Then the correct option is the first one, steel conducts thermal energy better than plastic.

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2. Can you place three forces of 5g, 6g, and 12g so they are in equilibrium. Justify your answer.
Bond [772]

Answer:

We cannot place three forces of 5g, 6g, and 12g in equilibrium.

Explanation:

Equilibrium means their sum must be zero.

Here the forces are 5g, 6g, and 12g.

For number of forces to be in equilibrium the magnitude of largest vector should be less than sum of the magnitude of other vectors.

Here

        Magnitude of largest force = 12 g

        Sum of magnitudes of other forces = 5g + 6g = 11g

       Magnitude of largest force >   Sum of magnitudes of other forces

So this forces cannot form equilibrium.

We cannot place three forces of 5g, 6g, and 12g in equilibrium.

4 0
3 years ago
Why does a balloon stick to a sweater after it has been rubbed against it?
Nataly [62]
Hello,

The balloon sticks to a sweater after it has been rubbed against it because once you rub a balloon against the sweater, the balloon steals electrons from the sweater, which leaves the sweater positively charged and the balloon negatively charged.

Mark brainliest if helped!

8 0
3 years ago
Read 2 more answers
In a summer storm, the wind is blowing at a velocity of 8 m/s north. Suddenly in 3 seconds, the winds velocity is 23 m/s north.
cricket20 [7]

Answer:a=v-u/t

=23-8/3

=5m/s hope you got your answer

Explanation:

8 0
3 years ago
A clothes dryer uses about 9 amps of current from a 240 volt line. How much power does it use?
Basile [38]
 240 x 9 = power
power= 2160 watts


4 0
3 years ago
Read 2 more answers
A ball is dropped from rest from the top of a cliff that is 24 m high. From ground level, a second ball is thrown straight upwar
sesenic [268]

Answer:

6.0 m below the top of the cliff

Explanation:

We can find the velocity at which the ball dropped from the cliff reaches the ground by using the SUVAT equation

v^2-u^2 = 2gd

where

u = 0 (it starts from rest)

g = 9.8 m/s^2 (acceleration of gravity, we assume downward as positive direction)

h = 24 m is the distance covered

Solving for h,

v=\sqrt{2gh}=\sqrt{2(9.8)(24)}=21.7 m/s

So the ball thrown upward is launched with this initial velocity:

u = 21.7 m/s

From now on, we take instead upward as positive direction.

The vertical position of the ball dropped from the cliff at time t is

y_1 = h - \frac{1}{2}gt^2

While the vertical position of the ball thrown upward is

y_2 = ut - \frac{1}{2}gt^2

The two balls meet when

y_1 = y_2\\h-\frac{1}{2}gt^2 = ut - \frac{1}{2}gt^2 \\h = ut \rightarrow t = \frac{h}{u}=\frac{24}{21.7}=1.11 s

So the two balls meet after 1.11 s, when the position of the ball dropped from the cliff is

y_1 = h -\frac{1}{2}gt^2 = 24-\frac{1}{2}(9.8)(1.11)^2=18.0 m

So the distance below the top of the cliff is

d=24.0 - 18.0 = 6.0 m

4 0
3 years ago
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