Consider a polymer formed by a chain process. By how much does the kinetic chain length change if the concentration of initiator
1 answer:
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Answer:
29.8 %
Explanation:
E=mcθ
where E is the energy added,m is the mass,c is the specfic heat capacity and θ is the change in temprature.
making m subject u get E/c<span>θ=m
</span><span>θ=(30-20)=10</span><span>
plugging the values we get :
</span>
<span>
solving it we get the answer that is 0.25kg or 250 grams
</span>
where E is the energy added,m is the mass,c is the specfic heat capacity and θ is the change in temprature.
making m subject u get E/c<span>θ=m
</span><span>θ=(30-20)=10</span><span>
plugging the values we get :
</span>
<span>
solving it we get the answer that is 0.25kg or 250 grams
</span>