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natita [175]
3 years ago
13

#2 6th grade science

Chemistry
1 answer:
kirill [66]3 years ago
6 0
The answer is 4 because in that century the romans empire was raided
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A.Force because your adding pressure to what you are pushing or pulling.
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What is one way to test whether an unknown solution is acidic or basic?
sertanlavr [38]

Answer: There are several ways. The first that comes to mind is a pH meter. A pH electrode Is lowered into the solution, and (Assuming) the pH Meter has been properly calibrated, and the temperature of the solution is set to the calibration of the Meter, the pH can be read directly from an analogue scale or digital readout. Below 7 is acidic, 7 is Neutral, (like Pure Water), and over 7 is Alkaline, or Basic.

A useful, but less accurate method is the use of any number of “pH Indicator Solutions”, which are essentially a type of various colored dyes that change color within differing pH ranges. Usually, if the pH is unknown, a small amount of solution is removed from the container and tested separately - in a “well plate”, or similar method.

These types of dyes, or Indicator Solutions, can be dried upon strips of “pH indicator Paper”, which, depending upon the type can be very useful when carrying out more precisely arrived at pH tests like Titration.

Just to see if a solution is “Acid” or “Base”, Litmus paper is used; “a Red color shows Acidity, and a Blue color, a Base”; ergo, “An Acid Solution will turn Litmus Paper, Red”.

4 0
3 years ago
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BARSIC [14]

A. Fission creates new elements from which electricity can be generated.

Hope this helps!

5 0
2 years ago
Read 2 more answers
5. A sample of pure acetyl salicylic acid had a mass of 0.268 grams. It was dissolved in NaOH and diluted to 500.00mL in a volum
Elza [17]

Answer:

a. 5.36x10⁻⁴ g/mL

b. 4.29x10⁻⁵ g/mL

Explanation:

As the units for concentration are not specified, I'll respond using g/mL.

a. We <em>divide the sample mass by the final volume</em> in order to <u>calculate the concentration</u>:

  • 0.268 g / 500 mL = 5.36x10⁻⁴ g/mL

b. We can use C₁V₁=C₂V₂ for this question:

  • 8.00 mL * 5.36x10⁻⁴ g/mL = C₂ * 100.00 mL
  • C₂ = 4.29x10⁻⁵ g/mL
4 0
3 years ago
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