The mass of Al that reacted with excess to produce 2.12 L of Hydrogen gas at STP will be 1.7 gm
<h3>What is Limiting reagent ?</h3>
The limiting reagent is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.
We're asked to find the number of grams of Al that reacted with excess to produce 2.12 L of Hydrogen gas at STP
Balanced chemical equation for this reaction :
2Al(s) + 6HCl(aq) --> 2AlCl₃(aq) +3H₂(g)
From the above equation, Using Limiting reagent concept, we can conclude that 3 mole of Hydrogen gas i.e, 67.2 Ltr (3 mole x 22.4 ltr) Hydrogen gas is produced by the consumption of 2 Al i.e, 54 gm (Mass = 2 mole x 27 g)
Therefore,
Mass of Al required to produce 2.12 ltr of Hydrogen gas = 54/67.2 x 2.12 = 1.7 gm
Hence, the mass of Al that reacted with excess to produce 2.12 L of Hydrogen gas at STP will be 1.7 gm
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