Answer:
Formula of EPSOM salt = MgSO4.7H2O
molecular mass of MgSO4.7H2O = atomic mass of Mg + atomic mass of S + 4 × atomic mass of O + 7 { 2 × atomic mass of H + atomic mass of O }
= 24 + 32 + 4× 16 + 7{ 2 × 1 + 16 } g/mol
= (24 + 32 + 64+ 126 ) g/mol
= 246 g/mol
molecular mass of total water = 7 × ( 2× atomic mass of H + atomic mass of O )
= 7 × 18 = 126 g/mol
now ,
% mass of H2O in EPSOM salt = {total molar mass of H2O/molar mass of Epsom salts }× 100
= {126/246 } × 100
= 12600/246
= 51.21 %
Explanation:
i have done it hope it helps
1) State the balanced chemical reaction
H2SO4 + 2NaOH -> Na2SO4 + 2H2O
2) State the molar ratios:
1 mol H2SO4 : 2 mol NaOH
3) Set the proportions using the number of moles of one rectant and x for the unknown one>
1 mol H2SO4 / 2 mol NaOH = x mol H2SO4 / 0.75 mol NaOH
=> x = 0.75 mol NaOH * [1 mol H2SO4 / 2 mol NaOH]
x = 0.375 mol H2SO4
4) Calculate the mass using the molar mass of H2SO4, MM.
MM = 2*1g/mol + 32.1 g/mol + 4*16 g/mol = 98.1 g/mol
mass = # of moles * molar mass = 0.375 mol * 98.1 g/mol = 36.79 g.
Answer: 36.8 grams
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Answer:
0.21 kg
Step-by-step explanation:
Volume of cola = 2.0 L × (33.8 fl oz/1L)
= 67.6 fl oz
Grams of sugar = 67.6 fl oz × (25 g sugar/8.0 fl oz)
= 210 g sugar
Kilograms of sugar = 210 g × (1 kg/1000 g)
= 0.21 kg