Answer:
The second ionization energy of an atom is always greater than its first ionization energy.
Explanation:
<em>Ionization energies are always negative quantities.</em> FALSE. Ionization energies are always positive because they represent the energy that has to be added to a neutral gaseous atom to remove 1 electron. By convention, energy absorbed goes with the positive sign.
X(g) + 1 I.E. ⇒ X(g)⁺ + 1 e⁻
<em>Oxygen has a larger first ionization energy than fluorine.</em> FALSE. First ionization energy (1 I.E) is the energy required to remove 1 electron from a neutral gaseous atom. First ionization energy for Oxygen is 13.61 eV and for Fluorine is 17.42 eV, that is, more energy is required to remove an electron from F than from O.
<em>The second ionization energy of an atom is always greater than its first ionization energy.</em> TRUE. The energy required to remove 1 electron from a +1 cation (second ionization energy) is always greater than the first ionization energy because of the attraction between the cation and the electron.
X(g)⁺ + 2 I.E. ⇒ X(g)⁺² + 1 e⁻
<em>The third ionization energy is the energy needed to ionize three electrons from a neutral atom.</em> FALSE. The third ionization energy (3 I.E.) is the energy required to remove 1 electron from a +2 cation.
X(g)⁺² + 3 I.E. ⇒ X(g)⁺³ + 1 e⁻
The molarity of a solution is defined as the moles of solute dissolved per kilogram of solvent. Therefore, we first compute the moles of KOH using:
Moles = mass / Mr
Moles = 23 / 56
Moles = 0.41
The volume of solvent is 1.6 liters
The density is 1 gram/cm³ = 1 kg/L
Mass of solvent = density * volume
Mass of solvent = 1 * 1.6
Mass of solvent = 1.6 kg
Molality = moles / kilogram
Molarity = 0.41 / 1.6
Molarity = 0.26
The molality of the solution is 0.26 molal.
Answer:
6KCl(aq) + Mg3(PO4)2(s) ... balanced equation
Explanation:
Answer:
2 the mass is greater than 10.0gram
Explanation:
2 the mass is greater than 10.0gram
