Answer:
The dimension is 
Explanation:
From the question we are told that
Here ![[J] = \frac{1}{L^2 T}](https://tex.z-dn.net/?f=%5BJ%5D%20%3D%20%5Cfrac%7B1%7D%7BL%5E2%20T%7D)
![[n] =\frac{1}{L^3}](https://tex.z-dn.net/?f=%5Bn%5D%20%3D%5Cfrac%7B1%7D%7BL%5E3%7D)
![[x] = L](https://tex.z-dn.net/?f=%5Bx%5D%20%3D%20L)
So
![\frac{1}{L^2 T} = -D \frac{d(\frac{1}{L^3})}{d[L]}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BL%5E2%20T%7D%20%3D%20%20-D%20%5Cfrac%7Bd%28%5Cfrac%7B1%7D%7BL%5E3%7D%29%7D%7Bd%5BL%5D%7D)
Given that the dimension represent the unites of n and x then the differential will not effect on them
So
![\frac{1}{L^2 T} = -D \frac{(\frac{1}{L^3})}{[L]}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BL%5E2%20T%7D%20%3D%20%20-D%20%5Cfrac%7B%28%5Cfrac%7B1%7D%7BL%5E3%7D%29%7D%7B%5BL%5D%7D)
=> 
=>
The answer to this question is B....hope this helps.
Answer:
24.7 ohms
Explanation:
Given in the question,
electric current = 3 A
potential difference = 74 V
Using ohm's law
<h3>V = IR</h3>
R = V/I
<em>here,</em>
<em>R = resistance of wire</em>
<em>V = potential difference</em>
<em>I = electric current</em>
<em />
plug value in the formula
R = 74/3
R = 24.7 ohms
Therefore, the resistance of the wire is, 24.7 ohms
The answer is diffraction or interference
Answer:
A. 2HCl + Mg(OH)2 + 2H2O + MgCl2
hope it helps
