Before answering this question, first we have to understand the effect of ratio of surface area to volume on the rate of diffusion.
The rate of diffusion for a body having larger surface area as compared to the ratio of surface area to volume will be more than a body having less surface area. Mathematically it can written as-
V∝ R [ where v is the rate of diffusion and r is the ratio of surface area to volume]
As per the question,the ratio of surface area to volume for a sphere is given ![0.08m^{-1}](https://tex.z-dn.net/?f=0.08m%5E%7B-1%7D)
The surface area to volume ratio for right circular cylinder is given ![2.1m^{-1}](https://tex.z-dn.net/?f=2.1m%5E%7B-1%7D)
Hence, it is obvious that the ratio is more for right circular cylinder.As the rate diffusion is directly proportional to the surface area to volume ratio,hence rate of diffusion will be more for right circular cylinder.
Hence the correct option is B. The rate of diffusion would be faster for the right cylinder.
Answer:
Johnny created an electromagnet out of a solenoid (a coil of wires with 20 loops), an iron core (of 1 nail), and a single 9 V battery. When Johnny does this, he creates a small magnetic field that allows him to pick up 2 paper clips. Using a CER format, explain to Johnny three things he could change that would increase the strength of his magnetic field and why each change increases the magnetic field. You may want to write three paragraphs to make this easier for the reader to understand
Answer
given,
For helium
Volume,V = 46 L
Pressure,P = 1 atm
Temperature,T = 25°C = 273 +25 = 298 K
R=0.0821 L . atm /mole.K
n₁ = ?
number of moles
we know
P V = n R T
![n_1 =\dfrac{46 \times 1}{0.0821\times 298}](https://tex.z-dn.net/?f=n_1%20%3D%5Cdfrac%7B46%20%5Ctimes%201%7D%7B0.0821%5Ctimes%20298%7D)
n₁ = 1.89 moles
For oxygen
Volume,V = 12 L
Pressure,P = 1 atm
Temperature,T = 25°C = 273 +25 = 298 K
R=0.0821 L . atm /mole.K
n₂ = ?
number of moles
we know
P V = n R T
![n_2 =\dfrac{12 \times 1}{0.0821\times 298}](https://tex.z-dn.net/?f=n_2%20%3D%5Cdfrac%7B12%20%5Ctimes%201%7D%7B0.0821%5Ctimes%20298%7D)
n₂ = 0.49 moles
Total volume of tank = 5 L
temperature of tank = 298 K
Partial pressure of helium
![P_1=\dfrac{n_1 R T}{V}](https://tex.z-dn.net/?f=P_1%3D%5Cdfrac%7Bn_1%20R%20T%7D%7BV%7D)
![P_1=\dfrac{1.89\times 0.0821\times 298}{5}](https://tex.z-dn.net/?f=P_1%3D%5Cdfrac%7B1.89%5Ctimes%200.0821%5Ctimes%20298%7D%7B5%7D)
P₁ = 9.25 atm
Partial pressure of oxygen
![P_2=\dfrac{n_2 R T}{V}](https://tex.z-dn.net/?f=P_2%3D%5Cdfrac%7Bn_2%20R%20T%7D%7BV%7D)
![P_2=\dfrac{0.49\times 0.0821\times 298}{5}](https://tex.z-dn.net/?f=P_2%3D%5Cdfrac%7B0.49%5Ctimes%200.0821%5Ctimes%20298%7D%7B5%7D)
P₂ = 2.39 atm
total pressure
P = P₁ + P₂
P = 9.25 + 2.39
P = 11.64 atm
Answer:
1500 mph
Explanation:
Take east to be +x and north to be +y.
The x component of the velocity is:
vₓ = 889 cos 0° + 830 cos 59°
vₓ = 1316.5 mph
The y component of the velocity is:
vᵧ = 889 sin 0° + 830 sin 59°
vᵧ = 711.4 mph
The speed is found with Pythagorean theorem:
v² = vₓ² + vᵧ²
v² = (1316.5 mph)² + (711.4 mph)²
v = 1496 mph
Rounded to two significant figures, the jet's speed relative to the ground is 1500 mph.
Answer:
It happens due to force of friction
Explanation:
If a body is performing a uniform motion and no external unbalanced force appears to apply on it, then the body will come to rest after certain time. The reason behind this is the force of friction that is applied in opposite direction of the motion. So, when there is no apparent unbalanced force it means that the only force acting on the body is the force of friction. This force of friction tends to stop the motion after some period of time, because it is acting in the direction opposite to that of motion.
Hence, the reason behind a body undergoing uniform motion eventually stops is <u>Force of Friction.</u>