Answer:
Given:
mass of the ball m = 0.144 kg
velocity v = 38 m/s
now, change in momentum
P = m v- ( - mv)
= 2 mv
=2 x (0.144) x (38)
= 10.944 kg-m/s
Impulse J= F. Δt
change in momentum is equal to impulse
J = 10.944 kg-m/s
we know force is equal to change in momentum per unit time
F = 13.68 x 10³ N
F = 13.68 kN
Answer:
49.79 m/s
Explanation:
Given:
Initial velocity of the roller coaster is,
Vertical drop or the displacement of the roller coaster is,
The displacement is negative as the motion is in downward direction.
Now, as the motion is in vertical direction only, the acceleration of the roller coaster will be due to gravity acting in the downward direction.
So, the acceleration of the roller coaster is,
Now, using the following equation of motion:
Where, 'v' is the velocity of the roller coaster at the bottom.
Plug in all the given values and solve for 'v'. This gives,
Therefore, the speed of the roller coaster at the bottom of the drop is 49.79 m/s.