Total resistance will be R1 + R2.
And the formula will be I equals V over R.
V=5
I=?
R=6
I= 0,83 amps
Answer:
Explanation:
initial velocity u = 0
final velocity v = 11.3 m /s
distance covered s = 12.8 m
v² = u² + 2 a s
11.3² = 0 + 2 x a x 12.8
a = 4.99 m /s²
again ,
v = u + a t
11.3 = 0 + 4.99 t
t = 2.26 s .
Rest of the sprint will be covered with uniform velocity .
Distance covered = 100 - 12.8 = 87.2 m
speed = 11.3 m /s
time taken = 87.2 / 11.3 = 7.7 s
Total time of 100 m sprint = 7.7 + 2.26 = 9.96 m .
b )
Let the time taken to reach the top speed be t .
acceleration a = 11.3 / t
distance covered s = 1/2 a t²
= .5 x (11.3 / t) x t²
= 5.65 t
Rest of the distance = 100 - 5.65 t
time taken to cover rest of the distance = (100 - 5.65 t ) / 11.3
Total time = (100 - 5.65 t / 11.3 ) + t = 9.75
100 - 5.65 t + 11.3 t = 11.3 x 9.75
100 + 5.65 t = 110.175
5.65 t = 10.175
t = 1.8
acceleration a = 11.3 / t
= 11.3 / 1.8
= 6.278 m /s²
distance covered in 1.8 s
s = 1/2 a t²
= .5 x 6.278 x 1.8²
= 10.17 m .
Answer:
m₃ = 30 kg
Explanation:
This is a problem of rotational equilibrium, let's write Newton's law for rotational equilibrium.
Let's fix our reference system in the support, the positive torques are those that create an anti-clockwise turn
Let's look for the distances to the point of support
The distance of man
x₁ = -3 m
The distance of the bar is
x₂ = L / 2 -3
x₂ = 10/2 -3
x₂ = 2 m
Remote object at the end
x₃ = L-3
x₃ = 10-3
x₃ = 7 m
They give us the mass of man (m1) and the mass of the bar (m2)
Let's write the torques
W₁ x₁ - W₂ x₂ - w₃ x₃ = 0
m₁ g 3 - m₂ g 2 - m₃ g 7 = 0
m₃ = (3m₁ -2m₂) / 7
Let's calculate
m₃ = (3 80 -2 15) / 7
m₃ = 30 kg
Answer:
Here you go!
Explanation:
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They will say hamsters are related to birds lol
