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Whitepunk [10]
3 years ago
10

how does a spectral signature help scientists determine the composition of planets and other stars???

Chemistry
1 answer:
sveticcg [70]3 years ago
6 0

Answer:

How do scientists determine the chemical compositions of the planets and stars? Each element absorbs light at specific wavelengths unique to that atom. When astronomers look at an object's spectrum, they can determine its composition based on these wavelengths. ... That fingerprint often appears as the absorption of light.

Explanation:

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When Oxygen in the air reacts with Iron, Iron Oxide forms.
Bess [88]

Answer:

I think its E. iron and iron oxide have the same properties if it's not e its d for sure

Explanation:

iron + oxygen → iron oxide. 4 Fe + 3 O2 → 2 Fe2O.

8 0
3 years ago
Use scientific notation to express 3.76 mg in grams
makkiz [27]
There are 1000 mg in 1 gram.
3.76/1000 = 0.00376

10^-3 = 0.001

0.001 x 3.76 = 0.00376

Answer is 
3.76 x 10^-3
7 0
3 years ago
How fast is an airplane traveling that accelerates at a rate of 20 mph per second for 30 seconds?
Nostrana [21]
Should be 600! hope this helps.
6 0
4 years ago
Read 2 more answers
A sample weighing 3.110 g is a mixture of Fe 2 O 3 (molar mass = 159.69 g/mol) and Al 2 O 3 (molar mass = 101.96 g/mol). When he
grandymaker [24]

Answer:

The mass fraction of ferric oxide in the original sample :\frac{723}{3110}

Explanation:

Mass of the mixture = 3.110 g

Mass of Fe_2O_3=x

Mass of Al_2O_3=y

After heating the mixture it allowed to react with hydrogen gas in which all the ferric oxide reacted to form metallic iron and water vapors where as aluminum oxide did not react.

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

Mass of mixture left after all the ferric oxide has reacted = 2.387 g

Mass of mixture left after all the ferric oxide has reacted = y

x=3.110 g- y=3.110 g - 2.387 g = 0.723 g

The mass fraction of ferric oxide in the original sample :

\frac{0.723 g}{3.110 g}=\frac{723}{3110}

5 0
3 years ago
ANSWER ASAP PLEASE I NEED HELP!
Vadim26 [7]

Answer:

If I remember correctly it should be B because it went from Cu^2 to Cu^0

Explanation:

7 0
2 years ago
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