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Zigmanuir [339]
3 years ago
13

How do you do problem #15?

Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
7 0
You would convert the cg to g. 1.66 cg is 0.0166 g. then you add. 0.398 + 0.0166 = 0.4146. the answer is 0.4146 grams.
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Provide any explanation at the subatomic level for how flame color is produced. Your answer should include a discussion of the e
weeeeeb [17]

Answer:

The flame provides an input of energy. It excites electrons in the material that is being burned. These electrons get promoted to a higher atomic energy level. When they return to a lower energy level, they release energy in the form of light (an output of energy.) The frequency of the light depends on the energy difference between the initial and final energy level of the electron. The color of the flame depends on the frequency of the emission.

Explanation:

There are multiple electron energy levels within an atom. During most of the time, electrons in an atom stay in levels with the lowest potential energy possible. However, when the atom gets heated (e.g., over a flame,) electrons will gain energy from the flame and move to levels of higher potential energy.

As more electrons get promoted, some will eventually fall back to their initial energy level. Electron energy levels in an atom are quantized. In other words, the energy difference between two levels is a definite value, and that no electron can exist between two energy levels.

Energy conserves. These potential energy needs to go somewhere. In the case of an electron transition, the potential energy that has been lost will be released as an electromagnetic emission. Keep in mind that only one photon will be released for each transition. That photon will account for all the potential energy differences \Delta E. The Planck-Einstein Relation gives the frequency \nu of that photon. That's the same as the frequency of the beam of light that is observed.  

\displaystyle \nu = \frac{\Delta E}{h},

where h is Planck's Constant.

The frequencies of most of these transitions are in the infrared region of the spectrum. If there are more than one few visible emissions, these emissions combine to produce a distinct flame color.

3 0
3 years ago
Which statement is true with respect to the investigation?
blagie [28]
What investigation????
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Practice Problems Exercise 8.6 Classify each of the following reactions in as many ways as possible.4N H3 (g) 5 O2 (g) n 4NO(g)
nikklg [1K]

Explanation :

(a) 4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)

This reaction is combustion reaction in which an oxygen react with a molecule to give its corresponding oxides ans water molecule.

(b) S_8(s)+8O_2(g)\rightarrow 8SO_2(g)

This reaction is a redox reaction or oxidation-reduction reaction in which sulfur get oxidized and oxygen get reduced.

(c) 2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3(s)

This reaction is a combination reaction in which the two reactants molecule combine to form a large molecule or product.

(d) 2AlN\rightarrow 2Al(s)+N_2(g)

This reaction is a decomposition reaction in which a large molecule or reactant decomposes to give two or more molecule or products.

(e) BaCl_2(aq)+Na_2SO_4(aq)\rightarrow BaSO_4(s)+2NaCl(aq)

This reaction is a double displacement reaction in which the cation of two reactants molecule exchange their places to give two different products.

(f) 2Cs(s)+Br_2(l)\rightarrow 2CsBr(s)

This reaction is a combination reaction in which the two reactants combine to form a large molecule or product.

(g) KOH(aq)+HCl(aq)\rightarrow H_2O(l)+KCl(aq)

This reaction is a double displacement reaction in which the cation of two reactants molecule exchange their places to give two different products.

(h) 2C_2H_2(g)+5O_2(g)\rightarrow 4CO_2(g)+2H_2O(l)

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6 0
3 years ago
Is the arctic circle generally warmer or colder than antartica
aev [14]
The answer would be, it would be warmer.
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3 years ago
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Ksenya-84 [330]

Answer and Explanation:

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Los diferentes tipos de fórmulas químicas son: fórmula empírica, fórmula molecular, fórmula semi-desarrollada y fórmula desarrollada. Tomando como ejemplo al compuesto <em>butano</em>:

- Fórmula empírica: C₂H₅ (indica que hay 2 átomos de C por cada 5 átomos de H; es una fórmula mínima)

- Fórmula molecular: C₄H₁₀ (indica que en realidad cada molécula de butano tiene 4 átomos de C y 10 átomos de H).

- Fórmula semi-desarrollada: CH₃CH₂CH₂CH₃ (indica el órden en que se unen los átomos en la molécula).

-Fórmula desarrollada: ver dibujo adjunto (indica cómo están unidos los átomos dentro de la molécula. Ahora vemos los enlaces entre los átomos y que los 2 átomos de C de los extremos están unidos a 3 átomos de H y a otro C, y los dos átomos de C del medio están unidos cada uno a 2 C y 2 H).

8 0
3 years ago
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