To determine the empirical formula for the compound that contains <span>0.979 g Na, 1.365 g S, and 1.021 g O, we convert these to mole units. The molar masses to be used are:
Molar mass of Na = 23 g/mol
</span>Molar mass of S = 32 g/mol
Molar mass of O = 16 g/ mol
The number of moles is obtained using the molar mass for each element.
moles Na = 0.979 g Na/ 23 g/mol Na = 0.04256
moles S = 1.365 g Na/ 32 g/mol Na = 0.04265
moles O = 1.021 g O/ 16 g/mol Na = 0.06326
We then divide each with the smallest number of moles obtained.
Na: 0.04256/ 0.04256 = 1
S: 0.04265/ 0.04256 = 1.002 ≈ 1
O: 0.06326/ 0.04256 = 1.49 ≈ 1.5
We then have an empirical formula of NaSO₁.₅. However, chemical formulas must have only integers as subscripts, thus, we multiply each to 2. The empirical formula is then Na₂S₂O₃ also known as sodium thiosulfate.
The number of protons and electrons of an atom is equal
and the amount can be obtained by looking at the atomic number of that atom or
element.
The atomic numbers are:
Gold = 79
Thallium = 81
So we are looking for the element with an atomic number of
80, that is:
Mercury
Answer:
<span>Mercury (Hg)</span>
Answer:
The answer to your question is: density = 5 g/cm³
Explanation:
Data
Volume = v = 2 m³
mass = m = 1 x 10⁴ kg
Density = d = ? g/cm³
Formula
density = mass/volume
Volume
1 m³ ------------------- 1 000 000 cm³
2 m³ ------------------ x
x = (2 x 1 000 000) / 1
x = 2 000 000 cm³
Mass
1 kg ------------------ 1000 g
1 x 10⁴ kg ------------ x
x = (1 x 10⁴ x 1000) / 1
x = 10 000 000 g
density = (10 000 000) / 2 000 000
density = 5 g/cm³
Answer: 3.4 L
Explanation:
To calculate the moles, we use the equation:
The balanced chemical equation for reaction of Hydrogen chloride gas with oxygen to form water vapor and chlorine gas.
According to stoichiometry :
4 moles of 
produce = 2 moles of 
Thus 0.29 moles of will produce =
of
Volume of 
Thus 3.4 L of of water would be produced by this reaction if 6.5 L of hydrogen chloride were consumed
