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Salsk061 [2.6K]
3 years ago
5

5. State the change in energy required to break the bonds in a water molecule.

Chemistry
1 answer:
Lorico [155]3 years ago
8 0

Answer:

I’m not for sure

Explanation:

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Which of the following describes the expected solubility of benzoic acid?
Igoryamba
I because it is an acid, it should be soluble in hexane
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2 years ago
Carbon has an atomic number of 6. How many electrons are in a carbon atom’s second energy level?
matrenka [14]
Carbon is an atom so electrons=protons 
<span>First shell has 2 electrons and the next 8 so with 6 electrons the first shell fills and 4 are left to go into the 2th shell.</span>
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3 years ago
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As discussed in class, the Fischer esterification reactants and products are at equilibrium. How was the equilibrium of the reac
german

Answer:

See explanation

Explanation:

The particular reactants in the Fischer esterification reaction were not stated.

Generally, a Fischer esterification is a reaction that proceeds as follows;

RCOOH + R'OH ⇄RCOOR' + H2O

This reaction occurs in the presence of an acid catalyst.

We can shift the equilibrium of this reaction towards the products side in two ways;

I) use of a large excess of either of the reactants

ii) removal of one of the products as it is formed.

Any of these methods shifts the equilibrium of the Fischer esterification reaction towards the products side.

4 0
3 years ago
Consider the reaction: N2(g) 2 O2(g)N2O4(g) Write the equilibrium constant for this reaction in terms of the equilibrium constan
Valentin [98]

Answer : The equilibrium constant for this reaction is, K=\frac{(K_b)^2}{K_a}

Explanation :

The given main chemical reaction is:

N_2(g)+2O_2(g)\rightarrow N_2O_4(g);  K

The intermediate reactions are:

(1) N_2O_4(g)\rightarrow 2NO_2(g);  K_a

(2) \frac{1}{2}N_2(g)+O_2(g)\rightarrow NO_2(g);  K_b

We are reversing reaction 1 and multiplying reaction 2 by 2 and then adding both reaction, we get:

(1) 2NO_2(g)\rightarrow N_2O_4(g);  \frac{1}{K_a}

(2) N_2(g)+2O_2(g)\rightarrow 2NO_2(g);  (K_b)^2

Thus, the equilibrium constant for this reaction will be:

K=\frac{1}{K_a}\times (K_b)^2

K=\frac{(K_b)^2}{K_a}

Thus, the equilibrium constant for this reaction is, K=\frac{(K_b)^2}{K_a}

5 0
2 years ago
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Delicious77 [7]
(4) C8H14 is your answer. A saturated hydrocarbon means that they have no double or triple bonds. C8H14 is an alkyne, which is an unsaturated hydrocarbon.
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3 years ago
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