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2 years ago

Write a balanced equation formed when the following elements react with oxygen:a)Zinc

Chemistry

1 answer:

Ainat [17]2 years ago

4 0

Explanation:

a) when zinc burnt in oxygen.

2Zn + O2 -----∆-----> 2ZnO(black residue)

b) when carbon burnt in oxygen.

C+O2----∆---> CO2.

c) when sulphur burnt in oxygen.

S+O2-----∆-----> SO2.

d) when Calcium burnt in oxygen.

2Ca+O2-----∆-----> 2CaO(black residue)

e) when Magnesium burnt in oxygen.

2Mg+O2-----∆----> 2MgO.

f) when sodium burnt in oxygen.

4Na+O2----∆-----> 2Na2O.

hope all these reactions help you.

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__SIO2+__HF--> __ H2SIF6+ __H2O balanced equation

Dima020 [189]

1,6,1,2 that should be the answer

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2 years ago

If an alloy is formed that is 50 mol% silver and 50 mol% gold, what is the karat number of the alloy?

Allisa [31]

Answer : 12 karat

Explanation : When pure gold is considered to be 24 karat then if its 50 mol% silver and 50 mol% silver then using karat scale calculation;

Karat/24 X 100 = 50 mol% (for gold) in alloy

So, Karat = (50 X 24) / 100 = 12 karat.

Hence the alloy will be of 12 karat.

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3 years ago

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What is true about the element calcium(Ca, atomic number 20)? Choose all that apply.

Marat540 [252]

It has 2 valence electrons

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3 years ago

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A chemistry student needs to standardize a fresh solution of sodium hydroxide. She carefully weighs out 192.mg of oxalic acid H2

kap26 [50]

Answer:

The molarity of the NaOH solution is 0.076 M

Explanation:

Step 1: Data given

Mass of oxalic acid = 192 mg = 0.192 grams

volume = 250 mL = 0.250 L

Molar mass oxalic acid = 90.03 g/mol

Step 2: The balanced equation

H2C2O4 + 2NaOH → Na2C2O4 + H2O

Step 3: Calculate moles of oxalic acid

Moles oxalic acid = 0.192 grams / 90.03 g/mol

Moles oxalic acid = 0.00213 moles

Step 4: Calculate molarity of oxalic acid

Molarity = Moles / volume

Molarity = 0.00213 moles / 0.250 L

Molarity = 0.00852 M

Step 5: Calculate Molarity of NaOH

2 Ca*Va = Cb*Vb

with Ca = Molarity of oxalic acid = 0.00852 M

with Va = volume of oxalic acid = 0.250 L

with Cb = Molarity of NaOH = TO BE DETERMINED

with Vb = volume of 0.0558 L

Cb = (2*0.00852 * 0.25) / 0.0558

Cb = 0.076 M

The molarity of the NaOH solution is 0.076 M

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2 years ago

What is the mass, in grams, of each elemental sample? a. 2.3 * 10-3 molSb b. 0.0355 mol Ba c. 43.9 mol Xe d. 1.3 mol W

belka [17]

Answer:

a. Sb =0.280048 g , b. Ba=4.875215 g , c. Xe=5763.631 g , d. W=238.992 g

Explanation:

number of moles = $\frac{mass}{molar mass}$

(a) For Sb, molar mass =121.76g/mol

number of moles =2.3* $10^{-3}$ mol

<em>mass= number of moles * molar mass</em>

mass =2.3* $10^{-3}$ *121.76

mass =0.280048 g

(b) for Ba, molar mass=137.33 g/mol

number of moles =0.0355 mol

mass = 0.0355 *137.33

mas = 4.875215 g

number of moles =43.9 mol

mass =43.9 *131.29

mass =5763.631 g

(d) for W, molar mass = 183.84 g/mol

number of moles = 1.3mol

mass = 1.3 *183.84

mass = 238.992 g

4 0

3 years ago