1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
cricket20 [7]
3 years ago
5

When 27.50 liters of oxygen gas reacts with excess hydrogen gas at STP how many grams of water is produced?

Chemistry
1 answer:
telo118 [61]3 years ago
5 0

<u>Answer: </u>The mass of water produced is 44.28 g

<u>Explanation:</u>

We are given:

Volume of oxygen gas = 27.50 L

At STP conditions:

22.4 L of volume is occupied by 1 mole of a substance

27.50 L of oxygen gas will be occupied by = \frac{1mol}{22.4L}\times 27.50L=1.23mol

The chemical equation for the formation of water follows:

2H_2+O_2\rightarrow 2H_2O

By the stoichiometry of the reaction:

If 1 mole of oxygen gas produces 2 moles of water

So, 1.23 moles of oxygen gas will produce = \frac{2}{1}\times 1.23=2.46mol of water

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

Molar mass of water = 18 g/mol

Plugging values in equation 1:

\text{Mass of water}=(2.46mol\times 18g/mol)=44.28g

Hence, the mass of water produced is 44.28 g

You might be interested in
Question 6 (1 point)
Mnenie [13.5K]

Answer:

The correct option is;

d 4400

Explanation:

The given parameters are;

The mass of the ice = 55 g

The Heat of Fusion = 80 cal/g

The Heat of Vaporization = 540 cal/g

The specific heat capacity of water = 1 cal/g

The heat required to melt a given mass of ice = The Heat of Fusion × The mass of the ice

The heat required to melt the 55 g mass of ice = 540 cal/g × 55 g = 29700 cal

The heat required to raise the temperature of a given mass ice (water) = The mass of the ice (water) × The specific heat capacity of the ice (water) × The temperature change

The heat required to raise the temperature of the ice from 0°C to 100°C = 55 × 1 × (100 - 0) = 5,500 cal

The heat required to vaporize a given mass of ice = The Heat of Vaporization × The mass of the ice

The heat required to vaporize the 55 g mass of ice at 100°C = 80 cal/g × 55 g = 4,400 cal

The total heat required to boil 55 g of ice = 29700 cal + 5,500 cal + 4,400 cal = 39,600 cal

However, we note that the heat required to vaporize the 55 g mass of ice at 100°C = 80 cal/g × 55 g = 4,400 cal.

The heat required to vaporize the 55 g mass of ice at 100°C = 4,400 cal

3 0
3 years ago
Which formula equation shows a reversible reaction?
pishuonlain [190]

Answer:2NaF is the correct one. It’s a simple combination and can be be split with relative ease

Explanation:

3 0
3 years ago
Read 2 more answers
If you react 2.00 g of hydrogen completely using 15.87 g of oxygen to produce water, how much water (in grams) will you have?
leonid [27]

Answer:

The amount (mass) of water we will have is 17.869 grams

Explanation:

The molar mass of hydrogen gas H₂ = 2.016 grams/mole

The molar mass of oxygen gas = 31.999 g/mol

Therefore, 2.00 g of hydrogen will give;

2.00/2.016 = 0.9921 moles of H₂ gas and

15.87 g of O₂ will give;

15.87/31.999 = 0.49595 moles

The reaction is as follows;

2H₂ (g) + O₂ (g) → 2H₂O (l)

Two moles of H₂ react with one mole of O₂ to produce two moles of H₂O

Therefore 0.9921 moles of H₂ will react with 0.9921/2 or 0.49595 moles of O₂ to produce 0.9921 moles of H₂O

From the above we note that all the H₂ and O₂ are completely consumed to form 0.9921 moles of H₂O

Molar mass of H₂O = 18.01528 g/mol

Number of moles = Mass/(Molar mass)

∴ Mass of H₂O = (Molar mass) × (Number of moles)

= 18.01528 g/mol × 0.9921 moles = 17.869 grams

Therefore the amount (mass) of water we will have = 17.869 grams.

8 0
3 years ago
Change 0.00765 kL into mL
bagirrra123 [75]

Answer:

7650

Explanation:

formula- multiply the volume value by 1e+6

4 0
4 years ago
Read 2 more answers
Is particle size one of the factors that affect solubility? How?
Over [174]
Hello!

The reduction in particle size results in an increased rate of solution. It occur because is harder for a a solvent to surround bigger molecules.

Hugs!
4 0
3 years ago
Other questions:
  • With some value of mixture CO and O2 density by Hydrogen is 15 . When reaction begun some time later density by Hydrogen of the
    9·1 answer
  • CaCO3(s) + HCl → CaCl2(s) + CO2(g) + H2O(g)
    15·1 answer
  • #18: all atoms of the same element have the same<br> a)number of neutrons<br> b)atomic number
    11·1 answer
  • What is the molar mass of a substance?
    7·2 answers
  • The nighttime and daytime temperatures on Mercury are 13 K and 683 K respectively. The melting point and boiling point of sulfur
    7·1 answer
  • A 51.9 g sample of quartz is put into a calorimeter (see sketch at right) that contains 300.0 g of water. The quartz sample star
    12·1 answer
  • Which statement is true about the speed of light? (2 points) Light travels relatively slowly. Distance in space is measured usin
    11·2 answers
  • Why do elements in group 8A (the noble gases) tend not to gain or lose electrons?
    11·1 answer
  • Which is the formula for nitrogen trihydride? NH3 N3H 3NH N3H3
    14·1 answer
  • the wind pushes a paper cup along the sand at a beach. the cup has a mass of 0.025 kg and accelerates at a rate of 5 m/s2. how m
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!