C) 24
Explanation:
When a radioactive isotope of Vanadium, V decays by producing a beta particle and gamma rays, the atomic number will be 24.
Vanadium is the 23rd element on the periodic table.
It has a mass number of 51.
atomic number is 23
⁵¹₂₃V
A beta particle is symbolized as °₋₁B
Gamma rays are represented by Y
Now to the equation:
⁵¹₂₃V → ₐⁿK + °₋₁B + Y
In a nuclear reaction the mass an atomic number is conserved
51 = n + 0
n = 51
23 = a -1
a = 24
We can see that the nuclide formed will have an atomic number of 24
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Magnesium would be more reactive.
The first half reaction is:
Sn+ -> Sn2+
You add 1 electron on the right side:
Sn+ -> Sn2+ + 1e-
The second half reacation is:
Ag+ -> Ag
You add 1 electron to the left side:
Ag+ + 1e- -> Ag
Then, you combine both reactions to get the balanced overall reaction since both half reactions have 1 electrons on the right and left side, respectively. You get:
Sn+ + Ag+ -> Sn2+ + Ag
The density of CO2 getting from experiment is 0.1/0.056 = 1.79 g/L. The percent error of this is (1.96 -1.79)/1.96*100%=8.67%. So the approximate percent error is 8.67%.