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soldier1979 [14.2K]
2 years ago
14

Describe a chemical test for water-

Chemistry
1 answer:
Mila [183]2 years ago
6 0

Answer:

Anhydrous copper (II) sulphate is white because it has no water in it. When drops of water are added, copper (II) sulphate turns blue. This colour change can be used to detect the presence of water (or water vapour).

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Five ways you can recycle​
Natasha_Volkova [10]
Answer:)

Top 5 Ways to Reuse and Recycle at Home
Repurpose Glass, Plastic and Cardboard Containers. ...
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2 years ago
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Make the following conversion. 0.075 m = _____ cm 7.5 75 0.0075 0.00075
oee [108]
7.5 is the answer. You have to move the decimal 2 places to the right.
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3 years ago
When a substance undergoes a chemical change, the product exhibits different physical properties than the starting material. Des
elena55 [62]

Answer:

I) Change in solubility

II) Change in boiling point

III) Change in colour

Explanation:

A chemical change involves formation of new products and is not reversible.

So, once two liquid solutions are mixed and a chemical change takes place, the new product will have the following:

- a new solubility rate, i.e it will dissolve at a rate different from the two liquid solution

- a new boiling point i.e it takes a new point at which its molecules liberate to yield vapour

- a new colour might be detected, as the individual solution each has its own colour

6 0
3 years ago
Calculate the reaction quotient Qp for the following redox reaction: 14H+ + Cr2O72- + 6Cl- ----> 2Cr3+ + 3Cl2 + 7H2O The reac
stich3 [128]

Answer:

Value of Q_{p} for the given redox reaction is 1.0\times 10^{-8}

Explanation:

Redox reaction with states of species:

14H^{+}(aq.)+Cr_{2}O_{7}^{2-}(aq.)+6Cl^{-}(aq.)\rightarrow 2Cr^{3+}(aq.)+3Cl_{2}(g)+7H_{2}O(l)

Reaction quotient for this redox reaction:

Q_{p}=\frac{[Cr^{3+}]^{2}.P_{Cl_{2}}^{3}}{[H^{+}]^{14}.[Cr_{2}O_{7}^{2-}].[Cl^{-}]^{6}}

Species inside third braket represent concentration in molarity, P represent pressure in atm and concentration of H_{2}O is taken as 1 due to the fact that H_{2}O is a pure liquid.

pH=-log[H^{+}]

So, [H^{+}]=10^{-pH}

Plug in all the given values in the equation of Q_{p}:

Q_{p}=\frac{(0.10)^{2}\times (0.010)^{3}}{(10^{-0.0})^{14}\times (1.0)\times (1.0)^{6}}=1.0\times 10^{-8}

7 0
3 years ago
How does each cell accomplish a wide variety of activities?
VLD [36.1K]
The organelles have specialized functions, (D)
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