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Misha Larkins [42]
3 years ago
8

Which statement best describes the benefit of having a universal system of measurement

Chemistry
2 answers:
goblinko [34]3 years ago
6 0
I think to is A
Because with that they work was more easy

Viefleur [7K]3 years ago
4 0
I think it would be c
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Where are galciers found
Fittoniya [83]

Answer: Antarctica or anywhere

Explanation:

I hope this helps im not sure if I’m correct but I’m sure u can find them anywhere cold

5 0
3 years ago
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How do carbon-12 and carbon-13 differ?
Feliz [49]

Answer:

They have different amounts of neutrons.

They have different mass numbers.

Explanation:

Carbon-12 and carbon-13 are two isotopes of the element carbon. The difference between carbon-12 and carbon-13 is the number of neutrons in each atom. Atoms of both isotopes of carbon contain 6 protons. Atoms of carbon-12 have 6 neutrons, while atoms of carbon-13 contain 7 neutrons. And because the mass number is the sum of protons and neutrons in the nucleus then will be different too. Atoms of carbon-12 have the mass number equal to  12 a.m.u. while atoms of carbon-13  have the mass number equal to 13 a.m.u. .

a.m.u. - atomic mass units

8 0
3 years ago
What is the most common ion charge of chromium? Where on the periodic table?​
raketka [301]

Answer:

i

Explanation:

7 0
2 years ago
Read 2 more answers
How many millimeters of 12 M HCI will be needed to create a 250-ML solution of 2 HCI?
Anestetic [448]
Call what you have to find is x
nHCl/V=12M 
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6 0
4 years ago
Pressure cookers allow food to cook faster because the higher pressure inside the pressure cooker increases the boiling temperat
KonstantinChe [14]

Answer:

\boxed{\text{139 $\, ^{\circ}$C}}

Explanation:

The question is asking, "At what temperature does the vapour pressure of water equal 3.4 atm?"

To answer this question, we can use the Clausius-Clapeyron equation:

\ln \left (\dfrac{p_{2}}{p_{1}} \right) = \dfrac{\Delta_{\text{vap}}H}{R} \left(\dfrac{1 }{ T_{1} } - \dfrac{1}{T_{2}} \right)

Data:

p₁ = 1 atm;    T₁ = 373.15C

p₂ = 3.4atm; T₂ = ?

R  = 8.314 J·K⁻¹mol⁻¹

\Delta_{\text{vap}}H = \text{39.67 kJ//mol}

(The enthalpy of vaporization changes with temperature. Your value may differ from the one I chose.)

Calculation:

\begin{array}{rcl}\ln \left (\dfrac{p_{2}}{p_{1}} \right)& = & \dfrac{\Delta_{\text{vap}}H}{R} \left( \dfrac{1}{T_{1}} - \dfrac{1}{T_{2}} \right)\\\\\ln \left (\dfrac{3.4}{1} \right)& = & \dfrac{39670}{8.314} \left(\dfrac{1 }{ 373.15 } - \dfrac{1}{T_{2}} \right)\\\\\ln3.4 & = & 4771 \left(\dfrac{1 }{ 373.15 } - \dfrac{1}{T_{2}} \right)\\\\1.224 & = & 12.78 - \dfrac{4771}{T_{2}}\\\\\dfrac{4771}{T_{2}} & = & 11.56\\\\\end{array}

T_{2} & = & \dfrac{4771}{11.56} = \text{412.6 K} = \textbf{139 $\, ^{\circ}$C}\\\\\text{The maximum temperature is } \boxed{\textbf{139 $\, ^{\circ}$C}}

7 0
3 years ago
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