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alina1380 [7]
3 years ago
15

Explain why a lithium ion (Li+) is smaller than a lithium atom (Li).

Chemistry
2 answers:
bonufazy [111]3 years ago
7 0

Answer:

Lithium ions are smaller than lithium atoms. This is because the lithium atom has 2 shells, while the ion just has one shell. Bromide ions are larger than bromine atoms, due to increased inter-electronic respulsion.

Explanation:

hope this helps! maybe mark me brainliest?

Vitek1552 [10]3 years ago
5 0
Li+ lost an electron, meaning it got more positive, but also smaller
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You hav to watch the video i don’t understand number 1 what to do help
UkoKoshka [18]
Ok so u js watch the video and go thru tbh e instructions and follow directions
5 0
2 years ago
Anions and cations are
Digiron [165]

Answer:

A cation is a positively charged ion, with fewer electrons than protons, while an anion is negatively charged, with more electrons than protons. Because of their opposite electric charges, cations and anions attract each other and readily form ionic compounds.

Explanation:

its science

5 0
4 years ago
Read 2 more answers
Given a 1.50 Liters of solution that contains 62.5 grams of magnesium oxide. What is the Molarity of that solution? Please show
qwelly [4]
Molarity= moles/ liters

first you need to calculate the moles using the molar mass of the molecule to convert grams to moles

molar mass MgO= 40.3 grams/ mole

62.5 gram MgO (1 mole/ 40.3 grams)= 1.55 mole

Molarity= 1.55 mole/ 1.50 Liters= 1.03 M
6 0
4 years ago
A gas has a volume of 560 mL at a temperature of –55°C. What volume will the gas occupy at
kap26 [50]

Answer: 778 ml

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=560ml\\T_1=-55^oC=(273-55)K=218K\\V_2=?\\T_2=30.0^oC=(273+30.0)K=303K

Putting values in above equation, we get:

\frac{560ml}{218K}=\frac{V_2}{303K}\\\\V_2=778ml

Thus volume the gas occupy at 30.0°C is 778 ml

7 0
3 years ago
Nitroglycerin is a dangerous powerful explosive that violently decomposes when it is shaken or dropped. The Swedish chemist Alfr
pshichka [43]

Answer:

1. 2 C₃H₅N₃O₉(l) ⇒ 3 N₂(g) + 1/2 O₂(g) + 5 H₂O(g) + 6 CO₂(g)

2. 146 g of nitroglycerin.

Explanation:

<em>1. Write a balanced chemical equation, including physical state symbols, for the decomposition of liquid nitroglycerin ( </em><em>C₃H₅N₃O₉</em><em>) into gaseous dinitrogen, gaseous dioxygen, gaseous water and gaseous carbon dioxide.</em>

The equation is:

C₃H₅N₃O₉(l) ⇒ N₂(g) + O₂(g) + H₂O(g) + CO₂(g)

Since atomicities in nitroglycerin are odd, it is easier to balance this equation by multiplying this compound by 2. The balanced equation is:

2 C₃H₅N₃O₉(l) ⇒ 3 N₂(g) + 1/2 O₂(g) + 5 H₂O(g) + 6 CO₂(g)

<em>2. Suppose 41.0L of carbon dioxide gas are produced by this reaction, at a temperature of −14.0°C and pressure of exactly 1 atm. Calculate the mass of nitroglycerin that must have reacted.</em>

First, we have to find the moles of CO₂ using the ideal gas equation.

P.V = n . R . T

where,

P is the pressure

V is the volume

n is the number of moles

R is the ideal gas constant (0.08206atm.L/mol.K)

T is the absolute temperature (-14.0 °C + 273.15 = 259.2 K)

P.V=n.R.T\\n=\frac{P.V}{R.T} =\frac{1atm . 41.0L}{(0.08206atm.L/mol.K).259.2K} =1.93mol

According to the balanced equation, 6 moles of CO₂ are formed when 2 moles of C₃H₅N₃O₉ react. And the molar mass of nitroglycerin is 227 g/mol. Then, for 1.93 moles of CO₂:

1.93mol(CO_{2}).\frac{2mol(nitroglycerin)}{6mol(CO_{2})} .\frac{227g(nitroglycerin)}{1mol(nitroglycerin)} =146g(nitroglycerin)

8 0
4 years ago
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