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adoni [48]
2 years ago
10

How does one determine a molecular formula from the epirical formula

Chemistry
1 answer:
rjkz [21]2 years ago
8 0

Answer:

C

Explanation:

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10. pls pls help me
vagabundo [1.1K]

Answer:

2c2h2+502=4co2+H2O

Explanation:

this is the answer

8 0
3 years ago
A tree trunk floating in the water<br> Balanced<br> Or<br> Unbalanced
mars1129 [50]

Answer:

Balanced

Explanation:

Please help me by marking me brainliest. I'm one away :)

3 0
3 years ago
What is the pH for a 0.10 M HCI solution at 25<br> degreesCelsius?
11Alexandr11 [23.1K]

Answer:

1.0

Explanation:

Hydrochloric acid is a strong acid, that is, an acid that dissociates completely, according to the following reaction.

HCl(aq) → H⁺(aq) + Cl⁻(aq)

Then, the concentration of H⁺ will be equal to the initial concentration of the acid, i.e., 0.10 M.

We can calculate the pH using the following expression.

pH = -log [H⁺] = -log 0.10 = 1.0

3 0
3 years ago
Which of the following will have the lowest boiling point?
mash [69]

Answer: C

Explanation:

3 0
4 years ago
Read 2 more answers
a solution with a transmittance of 0.44 is analyzed in a spectrophotometer with 6% stray light. calculate the absorbance reporte
IgorLugansk [536]

The absorbance reported by the defective instrument was 0.3933.

Absorbance A = - log₁₀ T

Tm = transmittance measured by spectrophotometer

Tm = 0.44

Absorbance reported in this equipment = -log₁₀ (0.44) = 0.35654

True absorbance can be calculated by true transmittance, Tm = T+S(α-T)

S = fraction of stray light = 6%= 6/100 = 0.06

α= 1, ideal case

T = true transmittance of the sample

Tm = T+S(α-T)

now, T= Tm-S/ 1-S = 0.44-0.06/ 1-0.06 = 0.404233

therefore, actual reading measured is A = -log₁₀ T = -log₁₀ (0.404233)

i.e; 0.3933

To know more about transmittance click here:

brainly.com/question/17088180

#SPJ4

3 0
1 year ago
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