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3 years ago

Please answer fast..........

Physics

2 answers:

natka813 [3]3 years ago

5 0

Yea your answer is subsonic wave I hope this help

Gnom [1K]3 years ago

4 0

Answer:

The correct answer is a. Subsonic

Hope this helps you^_^

Please mark as Brainliest.

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An output is a Push or pull _________________________ on the object

Ugo [173]

Answer:

The input force that you use on an inclined plane is the force with which you push or pull an object. The output force is the force that you would need to lift the object without the inclined plane. This force is equal to the weight of the object.

Explanation:

5 0

4 years ago

The _____ detects and disrupts terrorist activities before they occur and relies heavily on military force and national security

kobusy [5.1K]

The HOMELAND SECURITY detects and disrupts terrorist activities before they occur and relies heavily on military force and national security intelligence.

4 0

3 years ago

An airplane has a mass of 1.9E6 kg and the air flow past the

nordsb [41]

Answer:

$v_{1}=164.4 m/s$

Explanation:

The Bernoulli equation is:

$P+\frac{1}{2}\rho v^{2}+\rho gh=constant$ (1)

P is pressure related to the fluid
ρ is the density of the fluid (ρ(air)=1.23 kg/m³)
v is the speed of the fluid
h is the displacement from one position to the other

Now let's apply the equation (1), for our case:

$P_{1}+\frac{1}{2}\rho v_{1}^{2}=P_{2}+\frac{1}{2}\rho v_{2}^{2}$ (2)

here we assume that h is the same in both cases so it canceled out.

subscript 1 is related to the upper surface of the wings
subscript 2 is related to the low surface of the wings

Solving the equation for v₁ we have:

$v_{1}=\sqrt{\frac{2(P_{2}-P_{1})}{\rho}+v_{2}^{2}}$ (3)

Now, we know that pressure P=F/A (force over area)

$\Dela P=\frac{W}{A}=\frac{mg}{A}=\frac{1.9\cdot 10^{6}\cdot 9.81}{1.6\cdot 10^{3}} =11649.4 N/m^{2}$ (4)

Combining (3) and (4), we can find v1.

$v_{1}=\sqrt{\frac{2(11649.4)}{1.23}+90^{2}}$

$v_{1}=164.4 m/s$

I hope it helps you!

6 0

3 years ago

A forward-biased silicon diode is connected to a 6.0-V battery. Also in the circuit are three 220 Ω resistors connected in serie

o-na [289]

Answer:

Current in the circuit will be 0.024 A

Explanation:

We have given battery voltage v = 6 volt

Resistance R = 220 ohm

Diode potential $v_d$ = 0.7 volt

So voltage across the resistance = 6 - 0.7 = 5.3 volt

Current is given by $current=\frac{voltage}{reistance}=\frac{5.3}{220}=0.024A$

So current in the circuit will be 0.024 A

3 0

3 years ago

An alpha particle (the nucleus of a helium atom) consists of two protons and two neutrons, and has a mass of 6.64 * 10-27 kg. A

melamori03 [73]

Answer:

t = 4.21x10⁻⁷ s

Explanation:

The time (t) can be found using the angular velocity (ω):

$\omega = \frac{\theta}{t}$

Where θ: is the angular displacement = π (since it moves halfway through a complete circle)

We have:

$t = \frac{\theta}{\omega} = \frac{\theta}{v/r}$

Where:

v: is the tangential speed

r: is the radius

The radius can be found equaling the magnetic force with the centripetal force:

$qvB = \frac{mv^{2}}{r} \rightarrow r = \frac{mv}{qB}$

Where:

m: is the mass of the alpha particle = 6.64x10⁻²⁷ kg

q: is the charge of the alpha particle = 2*p (proton) = 2*1.6x10⁻¹⁹C

B: is the magnetic field = 0.155 T

Hence, the time is:

$t = \frac{\theta*r}{v} = \frac{\theta}{v}*\frac{mv}{qB} = \frac{\theta m}{qB} = \frac{\pi * 6.64 \cdot 10^{-27} kg}{2*1.6 \cdot 10^{-19} C*0.155 T} = 4.21 \cdot 10^{-7} s$

Therefore, the time that takes for an alpha particle to move halfway through a complete circle is 4.21x10⁻⁷ s.

I hope it helps you!

4 0

3 years ago

Please answer fast..........​

Please answer fast..........