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Ivanshal [37]
3 years ago
5

a man weighs 600 n while on the surface of earth. if he is transported to the planet mythos which has the same mass as earth but

a radius tjat os five times larger than earths , his weight would be
Physics
1 answer:
faltersainse [42]3 years ago
3 0

Answer:

24N

Explanation:

Calculation for what his weight would be

Let his WEIGHT on the surface of earth be 600 and Let the RADIUS be 25 which is (5^²) because we were told that the radius is FIVE TIMES larger than earths

Now let calculate his weight using this formula

Weight=Weight on Earth/Radius

Let plug in the formula

Weight=600N/5^²

Weight=600N/25

Weight=24N

Therefore his weight would be 24N

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A rock is thrown downward from an unknown height above the ground with an initial speed of 6.1 m/s. It strikes the ground 1.7 s
insens350 [35]

Answer:

24.531 m

Explanation:

t = Time taken = 1.7 s

u = Initial velocity = 6.1 m/s

v = Final velocity

s = Displacement

g = Acceleration due to gravity = 9.81 m/s² = a

Equation of motion

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=6.1\times 1.7+\dfrac{1}{2}\times 9.8\times 1.7^2\\\Rightarrow s=24.531\ m

The initial height of the rock above the ground is 24.531 m

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10.<br> Name THREE conductors and insulators with examples from everyday use.
Anna35 [415]

Answer:

Explanation:

Some common conductors are copper, aluminum, gold, and silver. Some common insulators are glass, air, plastic, rubber, and wood.

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4 years ago
The point is at the edge of the disk and the component bodies are:
Murrr4er [49]

Answer:

a. A uniform disk of radius and mass .

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What is the value of acceleration due to gravity at heght h=4re​
Norma-Jean [14]

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Explanation:

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3 years ago
Part A What will be the equilibrium temperature when a 227 g block of copper at 283 °C is placed in a 155 g aluminum calorimeter
stellarik [79]

Answer:

T = 20.84°C

Explanation:

From the law of conservation of energy:

Heat Lost by Copper Block = Heat Gained by Aluminum Calorimeter + Heat Gained by Water

m_cC_c\Delta T_c = m_wC_w\Delta T_w + m_aC_a\Delta T_a

where,

m_c = mass of copper = 227 g

m_w = mass of water = 844 g

m_a = mass of aluminum = 155 g

C_c = specific heat capacity of calorimeter = 385 J/kg.°C

C_w = specific heat capacity of water = 4200 J/kg.°C

C_a = specific heat capacity of aluminum = 890 J/kg.°C

\Delta T_c = change in temperature of copper = 283°C - T

\Delta T_w = change in temperature of water = T - 14.6°C

\Delta T_a = change in temperature of aluminum = T - 14.6°C

T = equilibrium temperature = ?

Therefore,

(227\ g)(385\ J/kg.^oC)(283^oC-T)=(844\ g)(4200\ J/kg.^oC)(T-14.6^oC)+(155\ g)(890\ J/kg.^oC)(T-14.6^oC)\\\\24732785\ J - (87395\ J/^oC) T = (3544800\ J/^oC) T - 51754080\ J+ (137950\ J/^oC) T-2014070\ J\\\\24732785\ J +51754080\ J+2014070\ J = (3544800\ J/^oC) T+(137950\ J/^oC+(87395\ J/^oC) T\\\\78560935\ J = (3770145\ J/^oC) T\\\\T = \frac{78560935\ J}{3770145\ J/^oC}

<u>T = 20.84°C</u>

8 0
3 years ago
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