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Airida [17]
3 years ago
7

A flatbed truck is supported by its four drive wheels, and is moving with an acceleration of 6.3 m/s2. For what value of the coe

fficient of static friction between the truck bed and a cabinet will the cabinet slip along the bed surface?
Physics
1 answer:
Levart [38]3 years ago
3 0

Answer:

Coefficient of static friction will be equal to 0.642  

Explanation:

We have given acceleration a=6.3m/sec^2

Acceleration due to gravity g=9.8m/sec^2

We have to find the coefficient of static friction between truck and a cabinet will

We know that acceleration is equal to a=\mu g, here \mu is coefficient of static friction and g is acceleration due to gravity

So \mu =\frac{a}{g}=\frac{6.3}{9.8}=0.642

So coefficient of static friction will be equal to 0.642

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SashulF [63]

Answer:

400m

Explanation:

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Let your initial displacement from your home to the store be

Dd

>

1 and your displacement from the store to your friend’s house

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2.

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Required: Dd

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T

Analysis: Dd

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1 1 Dd

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2

Solution: Figure 6 shows the given vectors, with the tip of Dd

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1

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2. The resultant vector Dd

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T is drawn in red,

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1 to the tip of Dd

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2. The direction of Dd

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T is [S].

Dd

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T measures 4 cm in length in Figure 6, so using the scale of

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2 years ago
Help !!!! Estimate the number of breaths taken by a person during 44 years?
Lisa [10]
44 x 12. I got the 12 from the total of 12 months in a year.


44 > 40

x
12 > 10
----------
The way my teacher taught me how to estimate is look at the neighbor to 44 and 12. The only time 44 can become 50, is when the neighbor is 5 or up. Same thing for 12. Now, multiply 40 and 10.

40 x 10 = 400.

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The mass of an object changes as the distance from the center of gravity changes.
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Answer:

true

Explanation:

this is the answer to this question

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