A flatbed truck is supported by its four drive wheels, and is moving with an acceleration of 6.3 m/s2. For what value of the coe
fficient of static friction between the truck bed and a cabinet will the cabinet slip along the bed surface?
1 answer:
Answer:
Coefficient of static friction will be equal to 0.642
Explanation:
We have given acceleration 
Acceleration due to gravity 
We have to find the coefficient of static friction between truck and a cabinet will
We know that acceleration is equal to
, here
is coefficient of static friction and g is acceleration due to gravity
So 
So coefficient of static friction will be equal to 0.642
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Answer:
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Explanation:
I think it’s D-decreases the amount of work.
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Vi=0
T=3.07s
D=46m
A=?
A=2(d)/t ^2
2(46)/3.07^2=9.8m/s^2
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