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artcher [175]
3 years ago
10

If a system requires 150 j of input work and produces 123 J of output work, whats its effiency

Physics
1 answer:
Yuki888 [10]3 years ago
4 0

The effiency of a machine is

                 (output work or energy) / (input work or energy) .

For the system described in the question, that's

                 (123 J) / (150 J) = 0.82  =  82% .

 
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The formula for the acceleration due to gravity is:

a = Gm/r²
where
G is the universal gravitational constant = 6.6726 x 10⁻¹¹ N-m²/kg²
m is the mass of planet
r is the radius of planet

So, if they have the same a:

m₁/r₁² = m₂/r₂²
So, if m₁ = m and r₂ = 2r₁,
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<em>Thus, the answer is D.</em>
8 0
3 years ago
The total yearly world consumption of energy is approximately 4.0 × 1020 J. How much mass would have to be completely converted
BabaBlast [244]

Answer:

m = 4.4 × 10³ kg

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Given that:

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m = \dfrac{4.0 \times 10^{20} }{(3\times 10^8)^2}

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