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artcher [175]
3 years ago
10

If a system requires 150 j of input work and produces 123 J of output work, whats its effiency

Physics
1 answer:
Yuki888 [10]3 years ago
4 0

The effiency of a machine is

                 (output work or energy) / (input work or energy) .

For the system described in the question, that's

                 (123 J) / (150 J) = 0.82  =  82% .

 
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Answer:

a=0.212 m/s²

Explanation:

Given that

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