We don't know if the road is perfectly straight between the intersections, or if the road bends, curves, or turns between them. So we don't have enough information to calculate the displacement between them.
But we <em>can</em> calculate the <u>distance</u> the car traveled between them.
Distance = (speed) (time)
Distance = (20 m/s) (120 s)
<em>Distance = 2,400 meters</em>
Answer:
Explanation:
We shall find first the velocity of ball at the time when string breaks. Let it be v . During its fall on the ground , 1.02 m below, we use the formula
h = 1/2 gt² where t is time of fall .
1.02 = 1/2 x 9.8 x t²
t²= .2081
t = .456
During this time it travels horizontally at distance of 2.5 m with uniform velocity of v
v x .456 = 2.5
v = 5.48 m /s
centripetal acceleration
= v² / r where r is radius of the circular path
= 5.48² / .478
= 62.82 m /s²
Answer:
Because the 'ing' in the English language is added to certain verbs to make them nouns.
Explanation:
Hope this helps :D
Answer:
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Answer:
period in case 2 is
times the period in case 1
Explanation:
The period of oscillation of a spring is given by:

where
m is the mass hanging on the spring
k is the spring constant
Therefore, in order to compare the period of the two springs, we need to find their m/k ratio.
We know that when a mass hang on a spring, the weight of the mass corresponds to the elastic force that stretches the spring by a certain amplitude A:

So we find

The problem tells us that the amplitude of case 1 is d, while the amplitude in case 2 is 2d. So we can write:
- for case 1:


- for case 2:


And by comparing the two periods, we find:

So, the period of oscillation in case 2 is
times the period of oscillation in case 1.