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kozerog [31]
3 years ago
7

Explain why nuclear fission and nuclear fusion release large amounts of energy

Physics
1 answer:
levacccp [35]3 years ago
8 0

Answer:

Because of the formula E=mc^2

Explanation:

In this problem we are describing two different processes:

  • Nuclear fission occurs when a heavy, unstable nucleus breaks apart into two or more lighter nuclei
  • Nuclear fusion occurs when two (or more) light nuclei fuse together producing a heavier nucleus

In both cases, the total mass of the final products is smaller than the total mass of the initial nuclei.

According to Einsten's formula, this mass difference has been converted into energy, as follows:

E=\Delta mc^2

where:

E is the energy released in the reaction

\Delta m is the mass defect, the difference between the final total mass and the initial total mass

c=3.0 \cdot 10^8 m/s is the speed of light

From the formula, we see that the factor c^2 is a very large number, therefore even if the mass defect \Delta m is very small, nuclear fusion and nuclear fission release huge amounts of energy.

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A car is traveling at 20 m/s. It takes the car 120s to go from one intersection to a second. What was the displacement of the ca
Bad White [126]

We don't know if the road is perfectly straight between the intersections,  or if the road bends, curves, or turns between them.  So we don't have enough information to calculate the displacement between them.

But we <em>can</em> calculate the <u>distance</u> the car traveled between them.

Distance = (speed) (time)

Distance = (20 m/s) (120 s)

<em>Distance = 2,400 meters</em>

7 0
3 years ago
A ball on the end of a string is whirled around in a horizontal circle of radius 0.478 m. The plane of the circle is 1.02 m abov
m_a_m_a [10]

Answer:

Explanation:

We shall find first the velocity of ball at the time when string breaks. Let it be v . During its fall on the ground , 1.02 m below, we use the formula

h = 1/2 gt² where t is time of fall .

1.02 = 1/2 x 9.8 x t²

t²= .2081

t = .456

During this time it travels horizontally at distance of 2.5 m with uniform velocity of v

v x .456 = 2.5

v  = 5.48 m /s

centripetal acceleration

= v² / r where r is radius of the circular path

= 5.48² / .478

= 62.82 m /s²

3 0
4 years ago
Why is it called a building if it’s already built
Jet001 [13]

Answer:

Because the 'ing' in the English language is added to certain verbs to make them nouns.

Explanation:

Hope this helps :D

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3 years ago
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Answer:

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3 0
3 years ago
In case 1, a block hanging on a spring oscillates with amplitude dd. in case 2, an identical block hanging on an identical sprin
Bogdan [553]

Answer:

period in case 2 is \sqrt{2} times the period in case 1

Explanation:

The period of oscillation of a spring is given by:

T=2 \pi \sqrt{\frac{m}{k}}

where

m is the mass hanging on the spring

k is the spring constant

Therefore, in order to compare the period of the two springs, we need to find their m/k ratio.

We know that when a mass hang on a spring, the weight of the mass corresponds to the elastic force that stretches the spring by a certain amplitude A:

mg = kA

So we find

\frac{m}{k}=\frac{A}{g}

The problem tells us that the amplitude of case 1 is d, while the amplitude in case 2 is 2d. So we can write:

- for case 1:

\frac{m}{k}=\frac{d}{g}

T_1=2\pi \sqrt{\frac{d}{g}}

- for case 2:

\frac{m}{k}=\frac{2d}{g}

T_2=2\pi \sqrt{\frac{2d}{g}}

And by comparing the two periods, we find:

\frac{T_2}{T_1}= \sqrt{2}

So, the period of oscillation in case 2 is \sqrt{2} times the period of oscillation in case 1.

4 0
3 years ago
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