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Paladinen [302]
3 years ago
7

What is the heliosheath?

Chemistry
1 answer:
Andru [333]3 years ago
6 0

Answer:

The heliosphere is the vast, bubble-like region of space that surrounds and is created by the Sun.

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What is the mole fraction, x, of solute and the molality for an aqueous solution that is 16.0 % NaOH by mass
Doss [256]
Step 1) identify the solvent and solute
      solvent= H2O 
      solute= NaOH
Step 2) Assume that there are 100 grams total. Assume that the percent of the compound present is the number of grams present as well
           100 g total
          16g NaOH 
            84g H20 
Step 3) convert grams to moles 
          84g H2O =4.64 mol H2O 
          19 g NaOH = 0.400 mol NaOH 
Step 4) mole fraction = moles A/(mol A + mol B +....) 
          X= 0.400/(0.400 + 4.64) = 0.079  (no units) 
Step 5) convert g of solvent to kg
        84 g H2O = 0.084 kg 
Step 6) molality = moles of solute/ kg of solvent 
           molality = 0.400 mol NaOH/ 0.084 kg H2O 
           molality=  4.76 m
  
          

3 0
3 years ago
How are chemical and mechanical weathering the same?
sasho [114]

Answer:

They break down materials into smaller pieces

Explanation:

Although using different methods

8 0
3 years ago
What's the difference between the structure of table salt and table sugar?
Karolina [17]
Table salt is a simple crystal of sodium chloride. Sugar is a complex carbohydrates molecule.
3 0
4 years ago
Find the volume of a rectangular prism that is<br> 25 cm by 10 cm by 15 cm.<br> height<br> length
Stolb23 [73]

Answer:

3750 cm.

Explanation:

You multiply the three side measurements to find the volume.

25cm·10cm·15cm

375cm·10cm

3750 cm.

<em><u>Hope this helps!</u></em>

4 0
3 years ago
Read 2 more answers
Data for the decomposition of hydrogen peroxide at some set temperature T is provided below. The rate law depends only on the co
Viktor [21]

Answer:

0.00442 s^{-1} is the value of the rate constant.

Explanation:

2 H_2O_2\rightarrow 2 H_2O + O_2

Let the order of the reaction be x.

The rate law of the reaction can be written as:

R=k[H_2O_2]^x

1. Rate of the reaction when concentration changes from 0.882 M to 0.697 M in 0 seconds  to 60 seconds.

R=-\frac{0.697 M-0.882 M}{60 s-0 s}=0.00308 M/s

0.00308 M/s=k[0.697 M]^x..[1]

2. Rate of the reaction when concentration changes from  0.697 M to 0.566 M in 240 seconds to 360 seconds.

R=-\frac{0.236M-0.372M}{120s-60 s}=0.00227 M/s

0.00218 M/s=k[0.236 M]^x..[2]

[1] ÷ [2]

\frac{0.00308 M/s}{0.00227 M/s}=\frac{k[0.697 M]^x}{k[0.236M]^x}

Solving fro x:

x = 0.92 ≈ 1

R=k[H_2O_2]^1

0.00308 M/s=k[0.697 M]^1

k=\frac{0.00308 M/s}{[0.697 M]^1}=0.00442 s^{-1}

0.00442 s^{-1} is the value of the rate constant.

5 0
4 years ago
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