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3 years ago

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Chemistry

1 answer:

erica [24]3 years ago

5 0

Answer:

The sphere on the left as it has more mass.

Explanation:

Inertia is the resistance to changes of motion.

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Iodine chloride, ICl, can be made by the following reaction between iodine, I2, potassium iodate, KIO3, and hydrochloric acid.

Vadim26 [7]

The balanced chemical reaction is:

2 I2 + KIO3 + 6 HCl ---------> 5 ICl + KCl + 3 H2O

We are given the amount of the product to be produced from the reaction. This will be the starting point of our calculations.

28.6 g ICl (1 mol / 162.35 g ICl ) ( 2 mol I2 / 5 mol ICl ) ( 253.81 g I2 / 1 mol I2 ) = 17.88 g I2

6 0

3 years ago

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Osmotic pressure Π is given by the relation:Π = iMRTwhere i is the van’t Hoff factor, M is the concentration of solute, R is the

lions [1.4K]

Answer: The concentration of solute is 0.503 mol/L

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=icRT$

where,

$\pi$ = osmotic pressure of the solution = 24 atm

i = Van't hoff factor = 2 (for NaCl)

c = concentration of solute = ?

R = Gas constant = $0.08\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[273+25]=298K$

Putting values in above equation, we get:

$24atm=2\times c\times 0.08\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\c=0.503mol/L$

Hence, the concentration of solute is 0.503 mol/L

5 0

3 years ago

Complete the reaction, which is part of the electron transport chain. The abbreviation Q represents coenzyme Q. Use the appropri

fredd [130]

Answer:

x = 2+

Explanation:

1) FADH2 + Q => FAD + QH2

Since H is added to Q

=> Reactant reduced is Q

(2) Balancing charges on both sides of the equation gives:

QH2 + 2 cyt c(Fe3+) => Q + 2 cyt c(Fe2+) + 2 H+

Thus x = 2+

7 0

3 years ago

What happens when an atom is exposed to an energy source such as electricity?

yarga [219]

It moves to a higher energy level

7 0

3 years ago

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Draw the major organic product for the reaction of 1-phenylpropan-1-one with the provided phosphonium ylide in part 1. In part 2

ipn [44]

Answer:

The major product formed is a benzyl allyl compound, namely 2-methylene propylbenzene

Explanation:

Part 1.

The product formed from this Wittig reaction with phosphonium ylide is a phenylallyl compound, 2-methylene propylbenzene. Structure and reaction synthesis is attached in file.

Part 2

The types of transformation involved are:

alkylation (as there is a transfer of alkyl group)
addition (reaction of ylide)

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3 years ago

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