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Nataliya [291]
3 years ago
7

Answer soon please ​

Chemistry
1 answer:
erica [24]3 years ago
5 0

Answer:

The sphere on the left as it has more mass.

Explanation:

Inertia is the resistance to changes of motion.

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Iodine chloride, ICl, can be made by the following reaction between iodine, I2, potassium iodate, KIO3, and hydrochloric acid.
Vadim26 [7]
The balanced chemical reaction is:

<span>2 I2 + KIO3 + 6 HCl ---------> 5 ICl + KCl + 3 H2O 
</span>
We are given the amount of the product to be produced from the reaction. This will be the starting point of our calculations.

28.6 g ICl (1 mol / 162.35 g ICl ) ( 2 mol I2 / 5 mol ICl ) ( 253.81 g I2 / 1 mol I2 ) = 17.88 g I2
6 0
3 years ago
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Osmotic pressure Π is given by the relation:Π = iMRTwhere i is the van’t Hoff factor, M is the concentration of solute, R is the
lions [1.4K]

<u>Answer:</u> The concentration of solute is 0.503 mol/L

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=icRT

where,

\pi = osmotic pressure of the solution = 24 atm

i = Van't hoff factor = 2 (for NaCl)

c = concentration of solute = ?

R = Gas constant = 0.08\text{ L atm }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

24atm=2\times c\times 0.08\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\c=0.503mol/L

Hence, the concentration of solute is 0.503 mol/L

5 0
3 years ago
Complete the reaction, which is part of the electron transport chain. The abbreviation Q represents coenzyme Q. Use the appropri
fredd [130]

Answer:

x = 2+

Explanation:

1) FADH2 + Q => FAD + QH2

Since H is added to Q

=> Reactant reduced is Q

(2) Balancing charges on both sides of the equation gives:

QH2 + 2 cyt c(Fe3+) => Q + 2 cyt c(Fe2+) + 2 H+

Thus x = 2+

7 0
3 years ago
What happens when an atom is exposed to an energy source such as electricity?
yarga [219]
It moves to a higher energy level<span />
7 0
3 years ago
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Draw the major organic product for the reaction of 1-phenylpropan-1-one with the provided phosphonium ylide in part 1. In part 2
ipn [44]

Answer:

The major product formed is a benzyl allyl compound, namely 2-methylene propylbenzene

Explanation:

<u>Part 1.</u>

The product formed from this Wittig reaction with phosphonium ylide is a phenylallyl compound, 2-methylene propylbenzene. Structure and reaction synthesis is attached in file.

<u>Part 2</u>

The types of transformation involved are:

  • alkylation (as there is a transfer of alkyl group)
  • addition (reaction of ylide)

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3 years ago
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