Question

A team of people who traveled to the North Pole by dogsled lived on butter because they needed to consume 6 000 dietitian's Calories each day. Because the ice there is lumpy and irregular, they had to help the dogs by pushing and lifting the load. Assume they had a 16-hour working day and that each person could lift a 500-N load. How many times would a person have to lift this weight 1.00 m upwards in a constant gravitational field, where (g = 9.80m/s2) where to do the work equivalent to 6 000 Calories?

Answer 1

Answer:

The right solution is "50200 days".

Explanation:

Given:

Calories intake,

= 6000 kcal,

or,

= $2.52\times 10^7 \ J$

Force,

= 500 N

As we know,

⇒ $Work \ done = Force\times distance$

Or,

⇒ $distance = \frac{Work \ done}{Force}$

By putting the values, we get

                  $=\frac{2.52\times 10^7}{500}$

                  $=0.502\times 10^5$

                  $=50200 \ m$

hence,

The number of days will be:

= $\frac{50200}{1}$

= $50200 \ days$